Submission #1162899

#TimeUsernameProblemLanguageResultExecution timeMemory
1162899panLibrary (JOI18_library)C++20
100 / 100
119 ms448 KiB
#include <bits/stdc++.h> //#include "includeall.h" //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> #define endl '\n' #define f first #define s second #define pb push_back #define mp make_pair #define lb lower_bound #define ub upper_bound #define input(x) scanf("%lld", &x); #define input2(x, y) scanf("%lld%lld", &x, &y); #define input3(x, y, z) scanf("%lld%lld%lld", &x, &y, &z); #define input4(x, y, z, a) scanf("%lld%lld%lld%lld", &x, &y, &z, &a); #define print(x, y) printf("%lld%c", x, y); #define show(x) cerr << #x << " is " << x << endl; #define show2(x,y) cerr << #x << " is " << x << " " << #y << " is " << y << endl; #define show3(x,y,z) cerr << #x << " is " << x << " " << #y << " is " << y << " " << #z << " is " << z << endl; #define all(x) x.begin(), x.end() #define discretize(x) sort(x.begin(), x.end()); x.erase(unique(x.begin(), x.end()), x.end()); #define FOR(i, x, n) for (ll i =x; i<=n; ++i) #define RFOR(i, x, n) for (ll i =x; i>=n; --i) #pragma GCC optimize("O3","unroll-loops") using namespace std; mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count()); //using namespace __gnu_pbds; //#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> //#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> typedef long long ll; typedef long double ld; typedef pair<ld, ll> pd; typedef pair<string, ll> psl; typedef pair<ll, ll> pi; typedef pair<pi, ll> pii; typedef pair<pi, pi> piii; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); ll n; vector<ll> order; int Query(const std::vector<int>& M); ll query(ll mid, ll x) { vector<int> now(n, 0); for (ll i=0; i<=mid; ++i) now[order[i]] = 1; ll ans = Query(now); now[x] = 1; return Query(now)==ans; } void Answer(const std::vector<int>& res); void Solve(int N) { vector<int> res(N, 1); n = N; if(n==1) {Answer(res); return;} order.clear(); for (ll i=0; i<n; ++i) order.pb(i); vector<int> now(n, 1); shuffle(all(order), rng); ll root = -1; for (ll i=0; i<n; ++i) { now[order[i]] = 0; if (Query(now)==1) {root = order[i]; break;} now[order[i]] = 1; } for (ll i=0; i<n; ++i) { res[i] = root+1; order.erase(find(all(order), root)); if (i==n-1) break; show(root); // find first ll lo = 0, hi = order.size()-1; while (lo!=hi) { ll mid = (lo + hi) >> 1; if (query(mid, root)) hi = mid; else lo = mid + 1; } if (lo < order.size()) root = order[lo]; } Answer(res); }
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