Submission #1161847

#TimeUsernameProblemLanguageResultExecution timeMemory
1161847Zero_OPCoin Collecting (JOI19_ho_t4)C++20
100 / 100
29 ms2988 KiB
#include <bits/stdc++.h> using namespace std; #define FOR(i, l, r) for(int i = (l); i < (r); ++i) #define ROF(i, r, l) for(int i = (r) - 1; i >= (l); --i) #define mp make_pair #define mt make_tuple #define ff first #define ss second #define all(v) begin(v), end(v) #define rall(v) rbegin(v), rend(v) #define sz(v) (int)v.size() #define pb push_back #define eb emplace_back #define compact(v) v.erase(unique(all(v)), end(v)) #define dbg(x) "[" #x " = " << (x) << "]" template<typename T> bool minimize(T& a, const T& b){ if(a > b) return a = b, true; return false; } template<typename T> bool maximize(T& a, const T& b){ if(a < b) return a = b, true; return false; } using ll = long long; using db = double; using ld = long double; using ull = unsigned long long; using pi = pair<int, int>; using pl = pair<ll, ll>; using pd = pair<db, db>; using vi = vector<int>; using vl = vector<ll>; using vb = vector<bool>; using vc = vector<char>; using vd = vector<db>; using vpi = vector<pi>; using vpl = vector<pl>; void setIO(){ ios_base::sync_with_stdio(0); cin.tie(0); #ifdef LOCAL freopen("task.inp", "r", stdin); freopen("task.out", "w", stdout); #endif // LOCAL } ll dist(ll x1, ll y1, ll x2, ll y2){ return abs(x1 - x2) + abs(y1 - y2); } int main(){ setIO(); int N; cin >> N; vi X(2 * N), Y(2 * N); ll base = 0; FOR(i, 0, 2*N){ cin >> X[i] >> Y[i]; tuple<ll, int, int> best(1e18, 0, 0); if(1 <= X[i] && X[i] <= N){ tuple<ll, int, int> U(dist(X[i], 2, X[i], Y[i]), X[i], 2); tuple<ll, int, int> D(dist(X[i], 1, X[i], Y[i]), X[i], 1); best = min(U, D); } else{ tuple<ll, int, int> DL(dist(1, 1, X[i], Y[i]), 1, 1); tuple<ll, int, int> DR(dist(N, 1, X[i], Y[i]), N, 1); tuple<ll, int, int> UL(dist(1, 2, X[i], Y[i]), 1, 2); tuple<ll, int, int> UR(dist(N, 2, X[i], Y[i]), N, 2); best = min({DL, DR, UL, UR}); } ll cost; int x, y; tie(cost, x, y) = best; X[i] = x; Y[i] = y; base += cost; } vector<array<int, 2>> cnt(N); // cout << base << '\n'; FOR(i, 0, 2 * N){ ++cnt[X[i]-1][Y[i]-1]; } //only (need[0] need[1] empty) or (have[0] have[1] empty) // FOR(j, 0, 2) FOR(i, 0, N){ // cout << cnt[i][j] << " \n"[i == N-1]; // } ll a = 0, b = 0, ans = 0; FOR(i, 0, N){ a += (cnt[i][0] - 1); b += (cnt[i][1] - 1); if(0 < a && b < 0){ //move up t coins from (?, 1) to (?, 2) ll delta = min(a, -b); // cout << "up : " << delta << '\n'; ans += delta; a -= delta; b += delta; } if(0 < b && a < 0){ //move down t coins from (?, 2) to (?, 1) ll delta = min(b, -a); // cout << "down : " << delta << '\n'; ans += delta; b -= delta; a += delta; } // cout << a << ' ' << b << '\n'; ans += abs(a); //if(a > 0) number of coins move from left to right else -a number of coins move from right to left ans += abs(b); // } cout << ans + base << '\n'; return 0; }
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