Submission #1161811

#TimeUsernameProblemLanguageResultExecution timeMemory
1161811Zero_OPCoin Collecting (JOI19_ho_t4)C++20
37 / 100
180 ms339968 KiB
#include <bits/stdc++.h> using namespace std; #define FOR(i, l, r) for(int i = (l); i < (r); ++i) #define ROF(i, r, l) for(int i = (r) - 1; i >= (l); --i) #define mp make_pair #define mt make_tuple #define ff first #define ss second #define all(v) begin(v), end(v) #define rall(v) rbegin(v), rend(v) #define sz(v) (int)v.size() #define pb push_back #define eb emplace_back #define compact(v) v.erase(unique(all(v)), end(v)) #define dbg(x) "[" #x " = " << (x) << "]" template<typename T> bool minimize(T& a, const T& b){ if(a > b) return a = b, true; return false; } template<typename T> bool maximize(T& a, const T& b){ if(a < b) return a = b, true; return false; } using ll = long long; using db = double; using ld = long double; using ull = unsigned long long; using pi = pair<int, int>; using pl = pair<ll, ll>; using pd = pair<db, db>; using vi = vector<int>; using vl = vector<ll>; using vb = vector<bool>; using vc = vector<char>; using vd = vector<db>; using vpi = vector<pi>; using vpl = vector<pl>; void setIO(){ ios_base::sync_with_stdio(0); cin.tie(0); #ifdef LOCAL freopen("task.inp", "r", stdin); freopen("task.out", "w", stdout); #endif // LOCAL } ll dist(ll x1, ll y1, ll x2, ll y2){ return abs(x1 - x2) + abs(y1 - y2); } int main(){ setIO(); int N; cin >> N; vi X(2 * N), Y(2 * N); ll base = 0; FOR(i, 0, 2*N){ cin >> X[i] >> Y[i]; tuple<ll, int, int> best(1e18, 0, 0); if(1 <= X[i] && X[i] <= N){ tuple<ll, int, int> U(dist(X[i], 2, X[i], Y[i]), X[i], 2); tuple<ll, int, int> D(dist(X[i], 1, X[i], Y[i]), X[i], 1); best = min(U, D); } else{ tuple<ll, int, int> DL(dist(1, 1, X[i], Y[i]), 1, 1); tuple<ll, int, int> DR(dist(N, 1, X[i], Y[i]), N, 1); tuple<ll, int, int> UL(dist(1, 2, X[i], Y[i]), 1, 2); tuple<ll, int, int> UR(dist(N, 2, X[i], Y[i]), N, 2); best = min({DL, DR, UL, UR}); } ll cost; int x, y; tie(cost, x, y) = best; X[i] = x; Y[i] = y; base += cost; } vector<array<int, 2>> cnt(N); // cout << base << '\n'; FOR(i, 0, 2 * N){ ++cnt[X[i]-1][Y[i]-1]; } //simulate the greedy queue<int> need[2], have[2]; //only (need[0] need[1] empty) or (have[0] have[1] empty) // FOR(j, 0, 2) FOR(i, 0, N){ // cout << cnt[i][j] << " \n"[i == N-1]; // } vi idx(2 * N); iota(all(idx), 0); sort(all(idx), [&](int i, int j){ return mp(X[i], Y[i]) < mp(X[j], Y[j]); }); vector<vl> dp(N+1, vl(N+1, 1e18)); dp[0][0] = 0; int num = 0; for(auto i : idx){ FOR(a, 0, N+1){ int b = num-a; if(0 <= b && b <= N){ if(a<N) minimize(dp[a+1][b], dp[a][b] + abs(a+1 - X[i]) + (Y[i] == 2)); if(b<N) minimize(dp[a][b+1], dp[a][b] + abs(b+1 - X[i]) + (Y[i] == 1)); } } ++num; } cout << base + dp[N][N] << '\n'; return 0; }
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