Submission #1159952

#	TimeUTC-0	Username	Problem	Language	Result	Execution time	Memory
1159952	2025-03-01 12:04:34	BentoOreo	Cyberland (APIO23_cyberland)	C++20	44 / 100	1035 ms	2162688 KiB

cyberland

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#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int,int>;
using pll = pair<long long int, long long int>;
const int inf = numeric_limits<int>::max();
const ll INF = numeric_limits<ll>::max();
const char sp = ' ';
const char nl = '\n';
/*
General Ideas 
From Discord:
1) We can make use of the zeros by dijkstra'sing from H to any point that ends in zero.
2) Check which nodes are reachable from the source. Which is "legit" nodes we can use
Idea
1) DP+Dijkstra distance holding
K <- number of div/2s operations i used
why?
 Div 2 cause dijkstra's to fail. Because values marked visited can actually have shorter paths if I visit a future node
and that has a div2 ability and go back to another I just was certain of finding the shortest path of.
So modifed dijkstras (d, node, k uses) and just dist[node] fails 
First things:
Mark all nodes reachable from 0
Dijsktra's from H
 
 
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