제출 #1157858

#제출 시각아이디문제언어결과실행 시간메모리
1157858arkanefuryRoad Construction (JOI21_road_construction)C++20
0 / 100
922 ms36876 KiB
#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define in insert
#define lb lower_bound
#define F first
#define S second
#define sz size()
#define int long long
#define all(v) v.begin(),v.end()
#define FOR1(x, n) for(int j = x; j <= n; j ++)
#define FOR(x, n, m, d) for(int x = n; x <= m; x += d)
#define FORR(x, n, m, d) for(int x = n; x >= m; x -= d)
#define nikita ios_base::sync_with_stdio(0), cin.tie(0);
const int N =  3e5+5;
int n,m,k,sum=0,x,y, ans, r, cnt, l, mod = 1e9+7, a[N], b[N];
string s, str;
set<pair<int, int>>st;
vector<pair<int, int>>v;
void yzero(){
    l = 1, r = 1e10;
    cnt = 0;
    while(l <= r){
        ans = 0;
        int md = (l + r) >> 1;
        FOR(i, 1, n, 1){
            cnt++;
            pair<int, int>ko = *st.lb({md + a[i]+1, i});
            if(ko.S==1e10)ko.F = v[v.sz-1].F, ko.S = n;
            else ko.F = v[ko.S-2].F, ko.S--;
            ans += (ko.S - i);
        }
        if(ans >= m)r = md - 1;
        else l = md + 1;
    }
    multiset<int>st1;
    FOR(i, 1, n, 1){
        pair<int, int>ko = *st.lb({l + a[i]+1, i});
        if(ko.S == 1e10)ko.F = a[n], ko.S=n;
        else ko.F = v[ko.S-2].F, ko.S--;
        FOR(j, i+1, ko.S, 1)st1.in(a[j]-a[i]);
    }
    for(auto i : st1){
        cout << i << '\n';
        m--;
        if(!m)break;
    }
}
void solve(){
    cin >> n >> m;
    FOR(i, 1, n, 1)cin >> a[i] >> b[i], v.pb({a[i], b[i]});
    if(n>1000){
    sort(all(v));
    FOR(i, 1, n,  1){
        st.in({v[i-1].F, i});
    }
    }
    
    if(n < 1000){
        multiset<int>lp;
        FOR(i, 1, n, 1){
            FOR(j, i+1, n, 1)lp.in(abs(a[i]-a[j]) + abs(b[i]-b[j]));
            for(auto i : lp){
                cout<<i<<'\n';
                m--;
                if(!m)return;
            }
        }
    }
    FOR(i,1,n,1)a[i] = v[i-1].F;
    st.in({1e10, 1e10});
    yzero();
}
signed main(){
    nikita
    int tt = 1;
    if(!tt)cin >> tt;
    FOR(i, 1, tt, 1)solve();
}
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