Submission #1153664

#TimeUsernameProblemLanguageResultExecution timeMemory
1153664PekibanTravelling Merchant (APIO17_merchant)C++20
0 / 100
50 ms2112 KiB
#include <bits/stdc++.h>

using namespace std;
using ll = long long;

const ll inf = 1e16;
int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    int n, m, k;
    cin >> n >> m >> k;
    ll a[n+1][2*k+1], DD[n+1][n+1], A[n+1][n+1];
    for (int i = 1; i <= n; ++i) {
        for (int j = 1; j <= 2*k; ++j)  cin >> a[i][j];
    }
    for (int i = 1; i <= n; ++i)    fill(DD[i], DD[i]+n+1, 1e12);
    for (int i = 1; i <= m; ++i) {
        int u, v; ll w;
        cin >> u >> v >> w;
        DD[u][v] = min(DD[u][v], w);
    }
    for (int z = 1; z <= n; ++z) {
        for (int i = 1; i <= n; ++i) {
            for (int j = 1; j <= n; ++j)    DD[i][j] = min({DD[i][z] + DD[z][j], DD[i][j]});
        }
    }
    for (int i = 1; i <= n; ++i) {
        for (int j = 1; j <= n; ++j) {
            A[i][j] = 0;
            for (int z = 1; z <= 2*k; z+=2) {
                if (a[i][z] != -1 && a[j][z+1] != -1) A[i][j] = max(A[i][j], a[j][z+1] - a[i][z]);
            }
        }
    }
    // for (int i = 1; i <= n; ++i) {
    //     for (int j = 1; j <= n; ++j) {
    //         cout << i << ' ' << j << ' ' << DD[i][j] << ' ' << A[i][j] << '\n';
    //     }
    // }
    ll l = 0, r = 1e9, ans=0;
    while (l <= r) {
        ll m = (l + r)/2;
        ll di[n+1][n+1];
        for (int i = 1; i <= n; ++i) {
            for (int j = 1; j <= n; ++j)    di[i][j] = A[i][j] - (m > inf / DD[i][j] ? inf : m * DD[i][j]);
        }
        for (int z = 1; z <= n; ++z) {
            for (int i = 1; i <= n; ++i) {
                for (int j = 1; j <= n; ++j)    di[i][j] = max(di[i][j], di[i][z] + di[z][j]);
            }
        }
        bool ok = 0;
        for (int i = 1; i <= n; ++i) {
            for (int j = 1; j <= n; ++j) {
                // if (m == 2) cout << m << ":" << di[i][j] << ' ' << A[i][j] << ' ' << DD[i][j] << ' ' << i << ' ' << j << endl;
                if (di[i][j] + di[j][i] >= 0)   ok = 1;
            }
        }
        if (ok)
            l = m+1, ans = m;
        else
            r = m-1;
    }
    cout << ans << '\n';
}
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