Submission #1153626

#TimeUsernameProblemLanguageResultExecution timeMemory
1153626MPGBitaro the Brave (JOI19_ho_t1)C++20
100 / 100
200 ms151692 KiB
//#pragma GCC optomize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("O3")
//#pragma GCC target("avx2")
//#pragma GCC target("sse,sse2,sse4.1,sse4.2") 



#include <bits/stdc++.h>
using namespace std;
typedef long long                           ll;
#define                                     max_heap priority_queue<pair <ll, pair <ll, ll>>>
#define                                     min_heap priority_queue<pair <ll, ll>, vector<pair <ll, ll>>, greater<pair <ll, ll>>>
//#define                                     min_heap priority_queue<ll, vector<ll>, greater<ll>>
#define                                     sariE cin.tie(NULL); cout.tie(NULL); ios_base::sync_with_stdio(false);
#define                                     filE freopen("in.txt", "r", stdin); freopen("out1.txt", "w", stdout); 
#define                                     endl '\n'
#define                                     md(a) (a % mod + mod) % mod
#define pb push_back
//cout << vectorprecision(5) << fixed << f;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

ll const maxn = 2e5 + 123;
ll const inf = 2e18;
ll const loG = 23;
//ll const mod = 1e9 + 7;
ll const mod = 998244353;
ll const sq = 350;
ll power(ll a, ll b, ll mod){if(b==0)return 1;if(b==1)return a;ll x = power(a, b / 2, mod);return (((x * x) % mod) * (b % 2 ? a : 1)) % mod;}


ll n, m, satr[3030][3030], soton[3030][3030];
string mp[3030];

void Solve(){

cin >> n >> m;
for (int i = 1; i < n + 1; i++){
    cin >> mp[i];
    mp[i] = ' ' + mp[i];
}
for (int i = 1; i < n + 1; i++){
    for (int j = 1; j < m + 1; j++){
        satr[i][j] = satr[i][j - 1];
        if (mp[i][j] == 'O')
            satr[i][j]++;
    }
}
for (int j = 1; j < m + 1; j++){
    for (int i = 1; i < n + 1; i++){
        soton[j][i] = soton[j][i - 1];
        if (mp[i][j] == 'I')
            soton[j][i]++;
    }
}
ll ans = 0;
for (int i = 1; i < n + 1; i++){
    for (int j = 1; j < m + 1; j++){
        if (mp[i][j] == 'J'){
            ll x = satr[i][m] - satr[i][j];
            ll y = soton[j][n] - soton[j][i];
            ans += x * y;
        }
    }
}

cout << ans << endl;

}



int main(){
sariE;// filE;



int test = 1;
//cin >> test;
while (test--) Solve();
return 0;
}
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