Submission #1147418

#TimeUsernameProblemLanguageResultExecution timeMemory
1147418koukirocksMarathon Race 2 (JOI24_ho_t3)C++20
7 / 100
13 ms19960 KiB
#include <bits/stdc++.h> #define F first #define S second #define speed ios_base::sync_with_stdio(0);cin.tie(0) #define all(x) x.begin()+1, x.end() using namespace std; typedef long long ll; typedef pair<int,int> pii; typedef pair<ll,ll> pll; template<class T> using vvector = vector<vector<T>>; const ll oo = 0x3f3f3f3f3f3f3f3f; const ll INF = 0x3f3f3f3f; int main() { speed; ll n,l; cin>>n>>l; l++; vector<ll> w(l+1); vector<ll> pre(l+1); vector<ll> pp(l+1); ll mx=0,mn=INF; for (int i=1;i<=n;i++) { ll x; cin>>x; x++; w[x]++; mx=max(mx,x); mn=min(mn,x); } for (int i=1;i<=l;i++) { pre[i]=pre[i-1]+w[i]; pp[i]=pp[i-1]+w[i]*i; } vector<ll> lft(l+2),rt(l+2); for (int i=1;i<=l;i++) { lft[i]=(w[i]?i:lft[i-1]); } rt[l+1]=l+1; for (int i=l;i>=1;i--) { rt[i]=(w[i]?i:rt[i+1]); } int q; cin>>q; while (q--) { ll s,e,t; cin>>s>>e>>t; s++;e++; ll nmn,nmx; if (e<s) { nmn=min(mn,e); nmx=max(mx,s); } else { nmn=min(mn,s); nmx=max(mx,e); } ll ans=min({ pp[l]-pp[e]+(e-2*nmn)*(pre[l]-pre[e]) + pre[e]*e-pp[e] + nmx-s+nmx-nmn+e-nmn, pp[l]-pp[e-1]-e*(pre[l]-pre[e-1]) + (2*nmx-e)*pre[e-1]-pp[e-1] + s-nmn+nmx-nmn+nmx-e, }); // cout<<pp[l]-pp[e]+(e-2*nmn)*(pre[l]-pre[e]) + pre[e]*e-pp[e] + nmx-s+nmx-nmn+e-nmn<<" c1\n"; // cout<<pp[l]-pp[e-1]-e*(pre[l]-pre[e-1]) + (2*nmx-e)*pre[e-1]-pp[e-1] + s-nmn+nmx-nmn+nmx-e<<" c2\n"; if (e<s) { ll mmx=max(e,lft[s]); ans=min(ans,pp[l]-pp[s]+(2*mmx-2*nmn-e)*(pre[l]-pre[s]) + pp[s]-pp[e-1]-e*(pre[s]-pre[e-1]) + (2*mmx-e)*pre[e-1]-pp[e-1] + nmx-s+nmx-nmn+mmx-nmn+mmx-e); // cout<<pp[l]-pp[s]+(2*mmx-2*nmn-e)*(pre[l]-pre[s]) <<" "<< pp[s]-pp[e-1]-e*(pre[s]-pre[e-1]) <<" "<< (2*mmx-e)*pre[e-1]-pp[e-1] <<" "<< nmx-s+nmx-nmn+mmx-nmn+mmx-e<<" c3\n"; } else { ll mmn=min(rt[s],e); ans=min(ans,pp[l]-pp[e]+(e-2*mmn)*(pre[l]-pre[e]) + (2*nmx-2*mmn+e)*pre[s-1]-pp[s-1] + e*(pre[e]-pre[s-1])-(pp[e]-pp[s-1]) + s-nmn+nmx-nmn+nmx-mmn+e-mmn); // cout<<pp[l]-pp[e]+(e-2*mmn)*(pre[l]-pre[e]) + (2*nmx-2*mmn+e)*pre[s-1]-pp[s-1] + e*(pre[e]-pre[s-1])-(pp[e]-pp[s-1]) + s-nmn+nmx-nmn+nmx-mmn+e-mmn<<" c3\n"; } cout<<(ans+n<=t?"Yes":"No")<<"\n"; // cout<<ans+n<<"\n"; } return 0; }
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