#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define sz size()
#define ff first
#define ss second
#define pb push_back
#define pii pair <int, int>
#define dur exit(0)
#define dur1 return(0)
const int N = 2e5 + 5;
pii p[N];
int n, m, k, q;
//map <int, int> m1, m2;
int main () {
// freopen ("input.txt", "r", stdin);
ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin >> n >> m >> k;
for (int i = 1; i <= k; ++i) {
cin >> p[i].ff >> p[i].ss;
}
sort (p + 1, p + k + 1);
// for (int i = 1; i <= k; ++i) {
// if (m1.find (p[i].ff) == m1.end()) {
// m1[p[i].ff] = i;
// }
// m2[p[i].ff] = i;
// }
cin >> q;
if (max (k, q) <= 5000) {
while ( q-- ) {
int x, y, x1, y1;
cin >> x >> y >> x1 >> y1;
if (x1 < x or y1 < y) {
cout << "No\n";
continue;
}
if (x1 - x > k) {
cout << "No\n";
continue;
}
// when it comes here x1 - x <= k --> it means every time you will go at most k times
for (int i = 1; i <= k; ++i) {
if (p[i].ff == x and p[i].ss >= y) {
x++;
y = p[i].ss;
}
if (x == x1) break;
}
if (x == x1 and y <= y1) {
cout << "Yes\n";
}
else cout << "No\n";
}
}
else {
while ( q-- ) {
int x, y, x1, y1;
cin >> x >> y >> x1 >> y1;
if (x1 < x or y1 < y) {
cout << "No\n";
continue;
}
if (x1 - x > k) {
cout << "No\n";
continue;
}
// then I will try to find a green grid range y to y1
auto tr = lower_bound (p + 1, p + k + 1, make_pair(x, y)) - p;
if (tr == k + 1 or p[tr].ff != x or p[tr].ss > y1) {
cout << "No\n";
}
else cout << "Yes\n";
}
}
}
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