Submission #1144743

#TimeUsernameProblemLanguageResultExecution timeMemory
1144743Zbyszek99A Difficult(y) Choice (BOI21_books)C++20
100 / 100
1 ms408 KiB
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include "books.h"
#define ll long long
#define ld long double
#define ull unsigned long long
#define ff first
#define ss second
#define pii pair<int,int>
#define pll pair<long long, long long>
#define vi vector<int>
#define vl vector<long long>
#define pb push_back
#define rep(i, b) for(int i = 0; i < (b); ++i)
#define rep2(i,a,b) for(int i = a; i <= (b); ++i)
#define rep3(i,a,b,c) for(int i = a; i <= (b); i+=c)
#define count_bits(x) __builtin_popcountll((x))
#define all(x) (x).begin(),(x).end()
#define siz(x) (int)(x).size()
#define forall(it,x) for(auto& it:(x))
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set;
//mt19937 mt;void random_start(){mt.seed(chrono::time_point_cast<chrono::milliseconds>(chrono::high_resolution_clock::now()).time_since_epoch().count());}
//ll los(ll a, ll b) {return a + (mt() % (b-a+1));}
const int INF = 1e9+50;
const ll INF_L = 1e18+40;
const ll MOD = 1e9+7;

void solve(int n, int k, long long A, int s) 
{
    int l = 1;
    int r = n;
    int poz = -1;
    while(l <= r)
    {
        int mid = (l+r)/2;
        if(skim(mid) < A)
        {
            poz = mid;
            l = mid+1;
        }
        else
        {
            r = mid-1;
        }
    }
    if(poz == -1)
    {
        impossible();
        return;
    }
    vl first_seg(k);
    vl second_seg(k);
    rep2(i,1,k) first_seg[i-1] = skim(i);
    ll first_sum = 0;
    forall(it,first_seg) first_sum += it;
    if(first_sum > A*2)
    {
        impossible();
        return;
    }
    if(first_sum >= A)
    {
        vi ans;
        rep2(i,1,k) ans.pb(i);
        answer(ans);
        return;
    }
    if(poz != n)
    {
        if(first_sum + skim(poz+1) - first_seg[k-1] <= A*2)
        {
            vi ans;
            rep2(i,1,k-1) ans.pb(i);
            ans.pb(poz+1);
            answer(ans);
            return;
        }
    }
    if(poz < k)
    {
        impossible();
    }
    rep2(i,1,k) second_seg[i-1] = skim(poz-i+1);
    rep(i,k)
    {
        first_sum -= first_seg[k-i-1];
        first_sum += second_seg[i];
        if(first_sum >= A && first_sum <= A*2)
        {
            vi ans;
            rep2(j,1,k-i-1) ans.pb(j);
            rep2(j,poz-i,poz) ans.pb(j);
            answer(ans);
            return;
        }
    }
    impossible();
}
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