Submission #1144739

#TimeUsernameProblemLanguageResultExecution timeMemory
1144739Zbyszek99A Difficult(y) Choice (BOI21_books)C++20
0 / 100
0 ms408 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include "books.h" #define ll long long #define ld long double #define ull unsigned long long #define ff first #define ss second #define pii pair<int,int> #define pll pair<long long, long long> #define vi vector<int> #define vl vector<long long> #define pb push_back #define rep(i, b) for(int i = 0; i < (b); ++i) #define rep2(i,a,b) for(int i = a; i <= (b); ++i) #define rep3(i,a,b,c) for(int i = a; i <= (b); i+=c) #define count_bits(x) __builtin_popcountll((x)) #define all(x) (x).begin(),(x).end() #define siz(x) (int)(x).size() #define forall(it,x) for(auto& it:(x)) using namespace __gnu_pbds; using namespace std; typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set; //mt19937 mt;void random_start(){mt.seed(chrono::time_point_cast<chrono::milliseconds>(chrono::high_resolution_clock::now()).time_since_epoch().count());} //ll los(ll a, ll b) {return a + (mt() % (b-a+1));} const int INF = 1e9+50; const ll INF_L = 1e18+40; const ll MOD = 1e9+7; void solve(int n, int k, long long A, int s) { int l = 1; int r = n; int poz = -1; while(l <= r) { int mid = (l+r)/2; if(skim(mid) < A) { poz = mid; l = mid+1; } else { r = mid-1; } } if(poz == -1) { impossible(); return; } vl first_seg(k); vl second_seg(k); rep2(i,1,k) first_seg[i-1] = skim(i); ll first_sum = 0; forall(it,first_seg) first_sum += it; if(first_sum > A*2) { impossible(); return; } if(first_sum >= A) { vi ans; rep2(i,1,k) ans.pb(i); answer(ans); return; } if(poz != n) { if(first_sum + skim(poz+1) - first_seg[k-1] <= A*2) { vi ans; rep2(i,1,k-1) ans.pb(i); ans.pb(poz+1); answer(ans); return; } } if(poz < k) { impossible(); } rep2(i,1,k) second_seg[i] = skim(poz-i+1); rep(i,k) { first_sum -= first_seg[k-i]; first_sum += second_seg[i]; if(first_sum >= A && first_sum <= A*2) { vi ans; rep2(j,1,k-i-1) ans.pb(j); rep2(j,poz-i,poz) ans.pb(j); answer(ans); return; } } impossible(); }
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