제출 #1141066

#제출 시각아이디문제언어결과실행 시간메모리
1141066ackhavaSelf Study (JOI22_ho_t2)C++20
62 / 100
91 ms8908 KiB
#include <bits/stdc++.h> #define REP(v, i, j) for (int v = i; v != j; v++) #define FORI(v) for (auto i : v) #define FORJ(v) for (auto j : v) #define OUT(v, a) \ FORI(v) \ cout << i << a; #define OUTS(v, a, b) \ cout << v.size() << a; \ OUT(v, b) #define in(a, n) \ REP(i, 0, n) \ cin >> a[i]; #define SORT(v) sort(begin(v), end(v)) #define REV(v) reverse(begin(v), end(v)) #define MEMSET(m) memset(m, -1, sizeof m) #define pb push_back #define fi first #define se second #define detachIO \ ios_base::sync_with_stdio(false); \ cin.tie(0); \ cout.tie(0); using namespace std; template<typename _Tp, typename _Alloc = std::allocator<_Tp> > bool operator==(const vector<_Tp, _Alloc>& __x, const vector<_Tp, _Alloc>& __y) { if(__x.size() != __y.size()) return false; return std::equal(__x.begin(), __x.end(), __y.begin()); } typedef pair<int, int> pii; typedef pair<pii, int> piii; typedef pair<pii, pii> piiii; const int MOD = 1e9+7; struct modint { long long val; modint() = default; modint(int _val): val(_val){} modint operator+(modint b){ return ((this->val + b.val)%MOD); } modint operator-(modint b){ return ((MOD + this->val - b.val)%MOD); } modint operator*(modint b){ return ((this->val * b.val)%MOD); } modint operator^(int a){ if(a==0)return 1; if(a==1)return *this; return (((*this)*(*this))^(a>>1))*((*this)^(a&1)); } }; modint invert(modint a){ return a^(MOD-2); } modint operator/(modint a, modint b){ return a*invert(b); } vector<long long> a,b; bool valid(long long n, long long m, long long t){ long long t0=t; long long need=0; REP(i,0,n){ t=t0; if((need)>(n*m))break; if(a[i]<=b[i]){ need+=(t+b[i]-1)/b[i]; if((need)>(n*m))break; continue; } long long run=(t+a[i]-1)/a[i]; t-=min(run,m)*a[i]; need+=min(run,m); if((need)>(n*m))break; if(t>0)need+=(t+b[i]-1)/b[i]; if((need)>(n*m))break; } return (need)<=(n*m); } int main(){ detachIO; long long n;cin>>n; long long m;cin>>m; REP(i,0,n){ long long x;cin>>x;a.pb(x); } REP(i,0,n){ long long x;cin>>x;b.pb(x); } long long l=0,r=2e16; long long ans; while(l<=r){ long long mid=(l+r)/2; if(valid(n,m,mid))ans=mid,l=mid+1; else r=mid-1; } cout<<ans<<'\n'; }
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