제출 #1141066

#제출 시각아이디문제언어결과실행 시간메모리
1141066ackhavaSelf Study (JOI22_ho_t2)C++20
62 / 100
91 ms8908 KiB
#include <bits/stdc++.h>
#define REP(v, i, j) for (int v = i; v != j; v++)
#define FORI(v) for (auto i : v)
#define FORJ(v) for (auto j : v)

#define OUT(v, a) \
    FORI(v)       \
    cout << i << a;
#define OUTS(v, a, b)      \
    cout << v.size() << a; \
    OUT(v, b)
#define in(a, n) \
    REP(i, 0, n) \
    cin >> a[i];

#define SORT(v) sort(begin(v), end(v))
#define REV(v) reverse(begin(v), end(v))
#define MEMSET(m) memset(m, -1, sizeof m)

#define pb push_back
#define fi first
#define se second

#define detachIO                      \
    ios_base::sync_with_stdio(false); \
    cin.tie(0);                       \
    cout.tie(0);
    
using namespace std;

template<typename _Tp, typename _Alloc = std::allocator<_Tp> >
bool operator==(const vector<_Tp, _Alloc>& __x, const vector<_Tp, _Alloc>& __y) {
    if(__x.size() != __y.size()) return false;
    return std::equal(__x.begin(), __x.end(), __y.begin());
}


typedef pair<int, int> pii;
typedef pair<pii, int> piii;
typedef pair<pii, pii> piiii;

const int MOD = 1e9+7;

struct modint {
    long long val;

    modint() = default;
    modint(int _val): val(_val){}
    modint operator+(modint b){ return ((this->val + b.val)%MOD); }
    modint operator-(modint b){ return ((MOD + this->val - b.val)%MOD); }
    modint operator*(modint b){ return ((this->val * b.val)%MOD); }
    modint operator^(int a){
        if(a==0)return 1;
        if(a==1)return *this;
        return (((*this)*(*this))^(a>>1))*((*this)^(a&1)); 
    }
};

modint invert(modint a){
    return a^(MOD-2);
}

modint operator/(modint a, modint b){
    return a*invert(b);
}

vector<long long> a,b;

bool valid(long long n, long long m, long long t){
    long long t0=t;
    long long need=0;
    REP(i,0,n){
        t=t0;
        if((need)>(n*m))break;
        if(a[i]<=b[i]){
            need+=(t+b[i]-1)/b[i];
            if((need)>(n*m))break;
            continue;
        }
        long long run=(t+a[i]-1)/a[i];
        t-=min(run,m)*a[i];
        need+=min(run,m);
        if((need)>(n*m))break;
        if(t>0)need+=(t+b[i]-1)/b[i];
        if((need)>(n*m))break;
    }
    return (need)<=(n*m);
}

int main(){
    detachIO;
    long long n;cin>>n;
    long long m;cin>>m;
    REP(i,0,n){
        long long x;cin>>x;a.pb(x);
    }
    REP(i,0,n){
        long long x;cin>>x;b.pb(x);
    }
    long long l=0,r=2e16;
    long long ans;
    while(l<=r){
        long long mid=(l+r)/2;
        if(valid(n,m,mid))ans=mid,l=mid+1;
        else r=mid-1;
    }
    cout<<ans<<'\n';
}
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