Submission #1137907

#	Time	Username	Problem	Language	Result	Execution time	Memory
1137907		jackofall718	Naboj (COCI22_naboj)	C++20	0 / 110	81 ms	14648 KiB

naboj

#include <bits/stdc++.h>
#include <chrono>
#define ll long long int
#define endl '\n'
#define vn vector<ll>
using namespace std;
using namespace std::chrono;
const int MAX_N = 1e9 + 7;
#define pii pair<ll,ll>
const ll INF = 0x3f3f3f3f3f3f3f3f;

#define pb push_back  
#define srt(vp) sort(vp.begin(), vp.end()) 

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    auto start = high_resolution_clock::now();
    
    ll n, m;
    cin >> n >> m;
    vector<vn> adj(n+1);
    vn deg(n+1, 0);  // degree vector to track the in-degrees
    
    for (int i = 0; i < m; i++) {
        ll u, v;
        cin >> u >> v;
        adj[v].pb(u);  // reverse the direction to match the problem's requirements
        deg[u]++;
    }

    priority_queue<int, vector<int>, greater<int>> noIndegree;
    for (int i = 1; i <= n; i++) {
        if (deg[i] == 0) noIndegree.push(i);
    }

    vn ans;

    while (!noIndegree.empty()) {
        ll u = noIndegree.top();
        noIndegree.pop();
        ans.pb(u);
        for (auto v : adj[u]) {
            deg[v]--;
            if (deg[v] == 0) noIndegree.push(v);
        }
    }

    if (ans.size() != n) {
        cout << -1 << endl;
    } else {
        // Adjust this part to implement the actual electron flow directions based on problem constraints
        cout << n << endl;
        bool check = true; // Let's assume initially we charge positively
        for (int i = 0; i < n; i++) {
            cout << ans[i] << " " << (check ? 1 : 0) << endl;
            check ^= 1; // Alternate the charge if necessary
        }
    }

    auto stop = high_resolution_clock::now();
    auto duration = duration_cast<microseconds>(stop - start);
    // Uncomment below to see the duration in microseconds
    // cout << "Time taken by function: " << duration.count() << " microseconds" << endl;

    return 0;
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 25
• Subtask 3: 0 / 70