Submission #1135718

#TimeUsernameProblemLanguageResultExecution timeMemory
1135718TAFHSimple game (IZhO17_game)C++20
100 / 100
236 ms34632 KiB
#include <bits/stdc++.h> // #include <ext/pb_ds/assoc_container.hpp> // #include <ext/pb_ds/tree_policy.hpp> // #pragma GCC optimize ("O3,unroll-loops") // #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") using namespace std; // using namespace __gnu_pbds; #define forn(i, n) for (int i = 0; i < n; i++) #define ull unsigned long long #define ll long long #define int long long #define SPEED \ ios_base::sync_with_stdio(false); \ cin.tie(0); \ cout.tie(0) // typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; const int N = 4e5 + 13; const int maxa = 2e5 + 13; const ll mod = 998244353; const int mxn = 1e6 + 13; const int mxa = 1e6 + 13; void prestart() {} int t[4 * mxa], dt[4 * mxa]; void push(int v) { dt[2 * v] += dt[v]; dt[2 * v + 1] += dt[v]; dt[v] = 0; } void update(int v, int l, int r, int tl, int tr, int dv) { int mid = (l + r) / 2; if (tr < l || r < tl) return; if (tl <= l && r <= tr) { dt[v] += dv; t[v] += dt[v]; if (l != r) push(v); dt[v] = 0; return; } t[v] += dt[v]; if (l != r) push(v); dt[v] = 0; update(2 * v, l, mid, tl, tr, dv); update(2 * v + 1, mid + 1, r, tl, tr, dv); t[v] = t[2 * v] + t[2 * v + 1]; } int get_i(int v, int l, int r, int idx) { int mid = (l + r) / 2; if (idx < l || r < idx) return -1; if (l == r && l == idx) { t[v] += dt[v]; dt[v] = 0; return t[v]; } t[v] += dt[v]; if (l != r) push(v); dt[v] = 0; return max(get_i(2 * v, l, mid, idx), get_i(2 * v + 1, mid + 1, r, idx)); } void start() { int n, m; cin >> n >> m; int h[n + 1]; forn(i, n) cin >> h[i + 1]; for(int i = 2; i <= n; i++) { update(1, 1, mxa, min(h[i - 1], h[i]), max(h[i - 1], h[i]), 1); } for(int i = 0; i < m; i++) { int t; cin >> t; if (t == 1) { int p, v; cin >> p >> v; if (p > 1) { update(1, 1, mxa, min(h[p - 1], h[p]), max(h[p - 1], h[p]), -1); update(1, 1, mxa, min(h[p - 1], v), max(h[p - 1], v), 1); } if (p < n) { update(1, 1, mxa, min(h[p + 1], h[p]), max(h[p + 1], h[p]), -1); update(1, 1, mxa, min(h[p + 1], v), max(h[p + 1], v), 1); } h[p] = v; } else { int h; cin >> h; cout << get_i(1, 1, mxa, h) << "\n"; } } } signed main() { SPEED; int t = 1; prestart(); // cin >> t; while (t--) { start(); } }
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