Submission #1131050

#TimeUsernameProblemLanguageResultExecution timeMemory
1131050vladiliusHedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++20
100 / 100
1542 ms213952 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; using pii = pair<int, int>; #define pb push_back #define ff first #define ss second #define arr3 array<int, 3> struct ST{ vector<int> t; int n; ST(int ns){ n = ns; t.resize(4 * n); } void upd(int v, int tl, int tr, int& p, int& x){ if (tl == tr){ t[v] = x; return; } int tm = (tl + tr) / 2, vv = 2 * v; if (p <= tm){ upd(vv, tl, tm, p, x); } else { upd(vv + 1, tm + 1, tr, p, x); } t[v] = max(t[vv], t[vv + 1]); } void upd(int p, int x){ upd(1, 1, n, p, x); } int get(int v, int tl, int tr, int& l, int& r){ if (l > tr || r < tl) return 0; if (l <= tl && tr <= r) return t[v]; int tm = (tl + tr) / 2, vv = 2 * v; return max(get(vv, tl, tm, l, r), get(vv + 1, tm + 1, tr, l, r)); } int get(int l, int r){ return get(1, 1, n, l, r); } }; int main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); int n, q; cin>>n>>q; vector<int> a(n + 2); for (int i = 1; i <= n; i++){ cin>>a[i]; } vector<int> log(n + 1); for (int i = 2; i <= n; i++) log[i] = log[i / 2] + 1; const int lg = log[n]; vector<vector<int>> sp(n + 1, vector<int>(lg + 1)); for (int i = 1; i <= n; i++) sp[i][0] = a[i]; for (int j = 1; j <= lg; j++){ for (int i = 1; i + (1 << j) <= n + 1; i++){ sp[i][j] = max(sp[i][j - 1], sp[i + (1 << (j - 1))][j - 1]); } } auto get = [&](int l, int r){ if (l > r) return 0; int k = log[r - l + 1]; return max(sp[l][k], sp[r - (1 << k) + 1][k]); }; vector<arr3> end[n + 1]; for (int i = 1; i <= q; i++){ int l, r, k; cin>>l>>r>>k; end[l].pb({r, k, i}); } deque<int> d1; a[n + 1] = 1e9 + 1; d1.pb(n + 1); ST T(n); deque<int> :: iterator it; vector<bool> out(q + 1); for (int i = n; i > 0; i--){ while (!d1.empty() && a[d1.front()] < a[i]){ T.upd(d1.front(), 0); d1.pop_front(); } int j = d1.front(), v = get(i + 1, j - 1); d1.push_front(i); if (v) T.upd(i, a[i] + v); for (auto [r, k, ii]: end[i]){ it = upper_bound(d1.begin(), d1.end(), r); it--; j = *it; v = T.get(1, j - 1); if (j < r){ v = max(v, a[j] + get(j + 1, r)); } out[ii] = (v <= k); } } for (int i = 1; i <= q; i++) cout<<out[i]<<"\n"; }
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