#include <bits/stdc++.h>
#define pb push_back
#define pf push_front
using namespace std;
#define F first
#define S second
typedef long long ll;
#define pii pair <int, int>
#define pll pair <ll, ll>
typedef long double ld;
const ll N = 3000 + 100, M = 500 + 10, len = 315, inf = 1e18;
const ll mod = 998244353;
ll um(ll a, ll b){
return (1LL * a * b) % mod;
}
ll subr(ll a, ll b){
return ((1LL * a - b) % mod + mod) % mod;
}
ll bp(ll x, ll step){
ll res = 1;
while(step){
if(step & 1) res = um(res, x);
x = um(x, x);
step /= 2;
}
return res;
}
ll inv(ll x){
return bp(x, mod - 2);
}
ll a[N], dp[N][N];
int main() {
//ios_base::sync_with_stdio(false);
//cin.tie(nullptr);
//cout.tie(nullptr);
int n, k;
cin >> n >> k;
for(int i = 1; i <= n; i++){
cin >> a[i];
}
for(int i = 0; i <= 100; i++){
for(int j = 0; j <= 100; j++){
dp[i][j] = -1;
}
}
dp[0][0] = 0;
for(int i = 1; i <= n; i++){
ll mx = 0;
for(int j = i; j <= n; j++){
mx = max(mx, a[j]);
for(int l = 1; l <= k; l++){
if(dp[i - 1][l - 1] == -1) continue;
if(dp[j][l] == -1) dp[j][l] = dp[i - 1][l - 1] + mx;
else dp[j][l] = min(dp[j][l], dp[i - 1][l - 1] + mx);
}
}
}
cout << dp[n][k];
return 0;
}
