Submission #1127446

#	Time	Username	Problem	Language	Result	Execution time	Memory
1127446		Lollospadalaser	Longest beautiful sequence (IZhO17_subsequence)	C++20	100 / 100	3252 ms	91904 KiB

subsequence

#include <algorithm>
#include <memory>
#include <queue>
#ifdef LOCAL
// #include "librerie locali/debugging.h"
#else
#pragma GCC optimize("Ofast,unroll-loops")
#endif
#include <bits/stdc++.h>
using namespace std;
#define rep(i, x) for (int i = 0; i < (x); i++)
#define reps(i,j,x) for(int i=(j);i<(x);i++)
#define repp(i,x) for(int i = 1; i <= (x); i++)
#define all(a) a.begin(),a.end()
#define allr(a) a.rbegin(),a.rend()
#define maxint numeric_limits<int>::max()
#define minint numeric_limits<int>::min()
#define maxll numeric_limits<ll>::max()
#define minll numeric_limits<ll>::min()
#define nl '\n'
#define f first 
#define s second
#define pb push_back
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int ui;
typedef pair<int, int> pi;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<pi> vpi;
typedef vector<pll> vpll;
typedef vector<vpi> vvpi;
typedef vector<vpll> vvpll;
typedef array<int, 3> i3;
typedef array<ll, 3> ll3;
typedef array<int, 4> i4;
typedef array<ll, 4> ll4;
typedef vector<i3> vi3;
typedef vector<ll3> vll3;
typedef vector<i4> vi4;
typedef vector<ll4> vll4;
typedef vector<bool> vb;
typedef vector<char> vc;
typedef vector<string> vs;
using ld = double;
 
constexpr ll mod = 1000000007;
 
ll nxt() {ll x;cin >> x;return x;}
template <class T> void make_unique(T &arr) {sort(all(arr)); arr.resize(unique(all(arr)) - arr.begin());}
void print(){cout<<endl;} template <typename T, typename... Types> void print(T var1, Types... var2) {cout<<var1<<" ";print(var2...);}
void printf(){cout<<nl;} template <typename T, typename... Types> void printf(T var1, Types... var2) {cout<<var1<<" ";printf(var2...);}
template <typename T> T maxm(T var) {return var;} template <typename T, typename... Types> T maxm(T var1, Types... var2) {return max(var1,maxm(var2...));}
template <typename T> T minm(T var) {return var;} template <typename T, typename... Types> T minm(T var1, Types... var2) {return min(var1,minm(var2...));}
ll lpow(ll base, ll exp){ll result = 1;for (;;){if (exp & 1)result *= base;exp >>= 1;if (!exp)break;base *= base;}return result;}
int log2_floor(unsigned long long i) {return i ? __builtin_clzll(1) - __builtin_clzll(i) : 0;}
template <typename T> T maxv(vector<T> &var) {T maxi=numeric_limits<T>::min();for(auto x : var)maxi=max(maxi,x);return maxi;}
template <typename T> T minv(vector<T> &var) {T mini=numeric_limits<T>::max();for(auto x : var)mini=min(mini,x);return mini;}
ll fastExp(ll a, ll b){ll res = 1;while(b){if(b&1)res = res*a%mod;a = a*a%mod;b>>=1;}return res;}
ll modInv(ll a){return fastExp(a,mod-2);}
ll gcd(ll a, ll b,ll &x, ll &y){if(b == 0){x = 1;y = 0;return a;}ll x1,y1;ll g = gcd(b,a%b,x1,y1);x=y1;y=x1- y1 * (a/b);return g;}
ll gcd(ll a, ll b){if(b == 0)return a;return gcd(b,a%b);}

void solve();
int main(){
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	#ifdef LOCAL
	freopen("snakes.in", "r", stdin);
	#endif
	// freopen("snakes.out", "w", stdout);
	cout << fixed << setprecision(15);
	int t=1;
	// cin>>t;
	rep(i,t){
		solve();
	}
}

#define maxm (10)
int dp[1<<maxm][1<<maxm][maxm+1];
int pos[1<<maxm][1<<maxm][maxm+1];

void solve(){
	// for(auto &x : pos)for(auto &y : x)for(auto &z : y)z=-1;
	int n = nxt();
	vi arr(n),common(n),prev(n,-1);
	rep(i,n)cin>>arr[i];
	rep(i,n)cin>>common[i];
	int ans = 0,start=-1;
	rep(i,n){
		int fir = arr[i]>>maxm,sec = arr[i]%(1<<maxm);
		int val=0;
		rep(j,1<<maxm){
			int eq = common[i] - __builtin_popcount(j & fir);
			if(eq < 0 || eq > maxm)continue;
			if(val < dp[j][sec][eq]){
				val = dp[j][sec][eq];
				prev[i]=pos[j][sec][eq];
			}
		}
		val++;
		if(val > ans){
			start = i;
			ans = val;
		}
		rep(j,1<<maxm){
			int eq = __builtin_popcount(sec & j);
			if(dp[fir][j][eq] < val){
				dp[fir][j][eq] = val;
				pos[fir][j][eq] = i;
			}
		}
	}
	cout<<ans<<nl;
	vi resp;
	while(start!=-1){
		resp.pb(start);
		start=prev[start];
	}
	reverse(all(resp));
	for(auto x : resp)cout<<x+1<<" ";cout<<nl;
}

• Subtask 1: 7 / 7
• Subtask 2: 16 / 16
• Subtask 3: 17 / 17
• Subtask 4: 60 / 60