Submission #112743

#TimeUsernameProblemLanguageResultExecution timeMemory
112743klungsElection Campaign (JOI15_election_campaign)C++14
20 / 100
1066 ms60640 KiB
#include<bits/stdc++.h>
 
 
#define pii pair<int,int>
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define pf push_front
#define pb2 pop_back
#define pf2 pop_front
#define line printf("\n")
#define pq priority_queue
#define rep(k,i,j) for(int k = (int)i;k<(int)j;k++)
#define repd(k,i,j) for(int k = (int)i;k>=(int)j;k--)
#define ll long long
#define ALL(a) a.begin(),a.end()
#define vi vector<int>
 
using namespace std;
 
int INF = 1e9+7;
 
#define vvi vector<vi>
 
int N, M;
vi A, B, C;
vvi adj;
 
void read(int _N, int _M, vi U, vi V, vi _A, vi _B, vi _C) {
  tie(N, M, A, B, C) = {_N, _M, _A, _B, _C};
  adj.resize(N);
  rep(k, 0, N - 1) {
    U[k]--; V[k]--;
    adj[U[k]].pb(V[k]);
    adj[V[k]].pb(U[k]);
  }
  rep(k, 0, M) {
    A[k]--; B[k]--;
  }
}
 
void bfs(int u, int v, vi &path) {
  vi par(N, -1);
  queue<int> q;
  q.push(u); par[u] = u;
  while (q.size()) {
    int a = q.front(); q.pop();
    for (int b : adj[a]) if (par[b] == -1) {
      q.push(b);
      par[b] = a;
    }
  }
  
  for (int b = v, a = par[v]; b != u; b = par[b], a = par[a]) {
    path.pb(b);    
  }
  path.pb(u);
}
 
vi par, hi;
void dfs(int a, int p) {
  par[a] = p; hi[a] = hi[p] + 1;
  for (int b : adj[a]) if (b != p) {
    dfs(b, a);
  }
}
void make_rooted_tree() { // root at 0
  par = hi = vi(N);
  dfs(0, 0);
}
 
vector<vvi> path;
vvi cost;
 
vi DP, SUM_CH;
int dp(int); int sum_ch(int);
 
int dp(int a) {
  int &ret = DP[a];
  if (ret != -1) return ret;
  
  int sum = sum_ch(a);
  ret = sum;
  rep(k, 0, path[a].size()) {
    int sum_ch_path = 0, c = cost[a][k];
    for (int ch : path[a][k]) {
      sum_ch_path += sum_ch(ch) - dp(ch);
    }
    int cur = sum + sum_ch_path + c;
    ret = max(ret, cur);
  }
  return ret;
}
 
int sum_ch(int a) {
  int &ret = SUM_CH[a];
  if (ret != -1) return ret;
  ret = 0;
  for (auto b : adj[a]) ret += dp(b);
  return ret;
}
 
int getMaximumVotes(int _N, int _M, vi _U, vi _V, vi _A, vi _B, vi _C) {
  read(_N, _M, _U, _V, _A, _B, _C);
  
  make_rooted_tree();
  
  // puts("rooted tree");
  path = vector<vvi>(N); 
  cost = vvi(N);
  rep(k, 0, M) { // prepare
    vi nodes; bfs(A[k], B[k], nodes);
    int uv = A[k];
    for (int a : nodes) // get lca
      if (hi[uv] > hi[a]) 
        uv = a;
    
    vi nodes_wo_lca;
    for (int a : nodes) if(a != uv)
      nodes_wo_lca.pb(a);
      
    path[uv].pb(nodes_wo_lca);
    cost[uv].pb(C[k]);
  }
  
  adj = vvi(N);
  rep(k, 1, N) adj[par[k]].pb(k);
  // puts("prepare");
  
  DP = SUM_CH = vi(N, -1);
  return dp(0);
}
 
// grader.cpp
#include <stdio.h>
#include <vector>
 
int main() {
  int N, M;
  std::vector<int> U, V;
  std::vector<int> A, B, C;
 
  scanf("%d", &N);
  U.resize(N-1); V.resize(N-1);
 
  for (int i = 0 ; i < N-1 ; i++) {
    scanf("%d %d", &U[i], &V[i]);
  }
  scanf("%d", &M);
  A.resize(M); B.resize(M); C.resize(M);
  for (int i = 0 ; i < M ; i++) {
    scanf("%d %d %d", &A[i], &B[i], &C[i]);
  }
 
  int ans = getMaximumVotes(N, M, U, V, A, B, C);
  printf("%d\n", ans);
  
  return 0;
}

Compilation message (stderr)

election_campaign.cpp: In function 'int main()':
election_campaign.cpp:145:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", &N);
   ~~~~~^~~~~~~~~~
election_campaign.cpp:149:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d", &U[i], &V[i]);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~
election_campaign.cpp:151:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", &M);
   ~~~~~^~~~~~~~~~
election_campaign.cpp:154:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d %d", &A[i], &B[i], &C[i]);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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