Submission #1127196

#TimeUsernameProblemLanguageResultExecution timeMemory
1127196bekzhan29Hard route (IZhO17_road)C++20
52 / 100
2096 ms51508 KiB
#include <bits/stdc++.h> using namespace std; #define pb push_back #define mp make_pair #define INF (long long)(2e15) #define mod2 998244353 #define mod 1000000007 #define eps 1e-9 #define abs(x) ((x)>=0?(x):-(x)) #define y1 solai #define fi first #define se second typedef int ll; typedef long double ld; typedef pair<ll,ll> pll; typedef pair<double,double> pdd; typedef pair<pll, ll> plll; mt19937 rng(29); const ll N=500100; ll n,x,y,ans,cnt=1,d[N],c[N]; vector<ll>v[N]; void dfs(ll x, ll pr=0) { d[x]=1; c[x]=1; for(ll to:v[x]) { if(to==pr) continue; dfs(to,x); if(d[to]+1>d[x]) { d[x]=d[to]+1; c[x]=c[to]; } else if(d[to]+1==d[x]) c[x]+=c[to]; } } bool cmp(ll a, ll b) { return d[a]>d[b]; } void solve(ll x) { dfs(x); sort(v[x].begin(),v[x].end(),&cmp); ll a=d[v[x][0]],b=d[v[x][1]],cc=d[v[x][2]]; if(a==cc) { ll sum=0; for(ll i=0;i<v[x].size();i++) { ll to=v[x][i]; if(d[to]!=a) break; if(ans==a*(b+cc)) { cnt+=c[to]*sum; } else if(ans<a*(b+cc)) { ans=a*(b+cc); cnt=c[to]*sum; } sum+=c[to]; } return; } if(a>b&&b==cc) { ll sum=0; for(ll i=1;i<v[x].size();i++) { ll to=v[x][i]; if(d[to]!=b) break; if(ans==a*(b+cc)) { cnt+=c[to]*sum; } else if(ans<a*(b+cc)) { ans=a*(b+cc); cnt=c[to]*sum; } sum+=c[to]; } return; } if(a>b&&b>cc) { ll sum=c[v[x][1]]; for(ll i=2;i<v[x].size();i++) { ll to=v[x][i]; if(d[to]!=cc) break; if(ans==a*(b+cc)) { cnt+=c[to]*sum; } else if(ans<a*(b+cc)) { ans=a*(b+cc); cnt=c[to]*sum; } sum+=c[to]; } return; } ll sum=c[v[x][0]]+c[v[x][1]]; for(ll i=2;i<v[x].size();i++) { ll to=v[x][i]; if(d[to]!=cc) break; if(ans==a*(b+cc)) { cnt+=c[to]*sum; } else if(ans<a*(b+cc)) { ans=a*(b+cc); cnt=c[to]*sum; } sum+=c[to]; } return; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin>>n; for(ll i=1;i<n;i++) cin>>x>>y,v[x].pb(y),v[y].pb(x); for(ll i=1;i<=n;i++) if(v[i].size()>2) solve(i); cout<<ans<<" "<<cnt<<endl; } /* 7 1 2 1 3 2 4 2 5 3 6 3 7 4 1 2 2 3 2 4 5 1 2 2 3 3 4 4 5 */
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