Submission #1122929

#	Time	Username	Problem	Language	Result	Execution time	Memory
1122929		gustavo_d	Towns (IOI15_towns)	C++17	0 / 100	254 ms	512 KiB

towns

#include "towns.h"
#include <bits/stdc++.h>
using namespace std;

const int MAXN = 110;
int cnt;
int cache[MAXN][MAXN];
int dist(int a, int b) {
	if (a > b) swap(a, b);
	if (a == b) return 0;
	if (cache[a][b] != -1) return cache[a][b];
	cnt--;
	assert(cnt >= 0);
	// cerr << "get "<< a << ' ' << b << endl;
	return cache[a][b] = getDistance(a, b);
}

int hubDistance(int n, int sub) {
	for (int i=0; i<n; i++) {
		for (int j=0; j<n; j++) {
			cache[i][j] = -1;
		}
	}
	cnt = n*(n-1)/2;
	int r = 1e9;
	if (sub == 1 or true) {
		for (int i=0; i<n; i++) {
			for (int j=i+1; j<n; j++) {
				// cerr << endl << endl;
				// cerr << "Olhando: " << i << ' ' << j << endl;
				map<pair<int, int>, int> mx_dist;
				for (int k=0; k<n; k++) {
					if (k == i or k == j) continue;
					int a = (dist(i, k) + dist(j, k) - dist(i, j)) / 2;
					int x = dist(i, k) - a;
					int y = dist(j, k) - a;
					mx_dist[{x, y}] = max({mx_dist[{x, y}], a, x, y});
					// cerr << k << ':' << x << ' ' << y << ' ' << a << endl;
					// cerr << dist(i, k) << ' ' << dist(j, k) << ' ' << dist(i, j) << endl;
				}
				int pf[(int)mx_dist.size()+1]; pf[0] = 0; int pf_i = 1;
				int last_x = 0;
				for (auto it=mx_dist.begin(); it != mx_dist.end(); it++, pf_i++) {
					auto [x, y] = it->first;
					int mx = it->second;
					pf[pf_i] = max(mx, x-last_x + pf[pf_i-1]);
					last_x = x;
				}
				int sf[(int)mx_dist.size()+1]; sf[(int)mx_dist.size()] = 0;
				int sf_i = (int)mx_dist.size()-1;
				int last_y = 0;
				for (auto it = mx_dist.end(); it != mx_dist.begin(); sf_i--) {
					it--;
					auto [x, y] = it->first;
					int mx = it->second;
					sf[sf_i] = max(mx, y-last_y + sf[sf_i+1]);
					last_y = y;
					// cerr << x << ' ' << y << '=' << max(sf[sf_i], pf[sf_i+1]) << endl;
				}
				for (int pt=0; pt<(int)mx_dist.size(); pt++) {
					if (max(pf[pt+1], sf[pt]) == 16) // cerr << pt << endl;
					r = min(r, max(pf[pt+1], sf[pt]));
				}
			}
		}
	}

	return r;
}

• Subtask 1: 0 / 13
• Subtask 2: 0 / 12
• Subtask 3: 0 / 13
• Subtask 4: 0 / 10
• Subtask 5: 0 / 13
• Subtask 6: 0 / 39