Submission #1118725

#TimeUsernameProblemLanguageResultExecution timeMemory
1118725Tai_xiuCommuter Pass (JOI18_commuter_pass)C++14
100 / 100
350 ms37372 KiB
#include<bits/stdc++.h> using namespace std; #define int long long #define i128 int128 #define ii pair<int,int> #define ld long double #define vi vector<int> #define vvi vector<vi> #define vii vector<pair<int,int>> #define FOR(i,a,b) for (int i=a;i<=b;i++) #define FOR1(i,a,b,c) for (int i=a;i<=b;i+=c) #define REP(i,a,b) for (int i=a;i>=b;i--) #define REP1(i,a,b,c) for(int i=b;i>=a;i-=c) #define endh '\n'; #define len(a) a.length() #define pb(c) push_back(c) #define elif else if #define ppb() pop_back() #define rong std::npos #define all(c) (c.begin(),c.end()) #define Z int #define R double #define lcm(a,b) ((int) (a/__gcd(a,b))*b) #define mk(a,b) make_pair(a,b) Z dx4[]={-1,1,0,0}; Z dy4[]={0,0,1,-1}; string co="YES",khong="NO"; const int mod=1e9+7; const Z maxn=200005; Z n,m,s,t,toi,kurumi; Z ds[maxn],dt[maxn],du[maxn],dv[maxn]; vii g[maxn]; vi g1[maxn]; const Z oo=1e18; void dijkstra(Z sink,Z d[]) { FOR(i,1,n) d[i]=oo; d[sink]=0; priority_queue<ii,vii,greater<ii>>q; q.push(mk(0,sink)); while(!q.empty()){ ii top=q.top();q.pop(); Z u=top.second; Z w=top.first; if (w>d[u]) continue; for (ii i:g[u]){ Z u1=i.first; Z w1=i.second; if (d[u]+w1<d[u1]){ d[u1]=d[u]+w1; q.push(mk(d[u1],u1)); } } } } Z ans=1e18; Z dp1[maxn],dp2[maxn]; bool check[maxn]; void dfs(Z u) { check[u]=1; for (Z v:g1[u]){ if (check[v]==0){ dfs(v); } dp2[u]=min(dp2[v],dp2[u]); } } void calc(Z d1[],Z d2[]) { FOR(i,1,n) dp1[i]=d1[i]; FOR(i,1,n) check[i]=0; FOR(i,1,n) dp2[i]=d2[i]; FOR(i,1,n) { if (check[i]==0) dfs(i); } FOR(i,1,n){ ans=min(ans,dp2[i]+d1[i]); } } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); // freopen("commuter.inp","r",stdin); // freopen("commuter.out","w",stdout); cin>>n>>m>>s>>t; cin>>toi>>kurumi; FOR(i,1,m){ Z u,v,w; cin>>u>>v>>w;; g[u].pb(mk(v,w)); g[v].pb(mk(u,w)); } dijkstra(s,ds); dijkstra(t,dt); dijkstra(toi,du); dijkstra(kurumi,dv); FOR(i,1,n){ for ( ii v:g[i]){ if (ds[i]+dt[v.first]+v.second==ds[t]) g1[i].pb(v.first); } } calc(du,dv); calc(dv,du); // FOR(i,1,n) cout<<ds[i]<<" "; // cout<<'\n'; // FOR(i,1,n) cout<<dt[i]<<" "; // cout<<'\n'; cout<<ans; }
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