Submission #1116866

#	Time	Username	Problem	Language	Result	Execution time	Memory
1116866		SN0WM4N	Art Exhibition (JOI18_art)	C++17	100 / 100	151 ms	15976 KiB

art

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define sort undefined_function // To use stable_sort instead sort 
#define bpc __builtin_popcount
#define ull unsigned long long
#define ld double
#define ll long long
#define mp make_pair
#define F first
#define S second

# pragma GCC optimize("O2")
//pragma GCC optimize("my solution")

using namespace __gnu_pbds;
using namespace std;

typedef tree<long long, null_type, less_equal<long long>,
    rb_tree_tag, tree_order_statistics_node_update> Tree;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

const ll INF = 9223372036854775807LL;
const ll inf = 2147483647;
const ll MOD = 1e9 + 7; //[998244353, 1e9 + 7, 1e9 + 13]

ll gcd(ll a, ll b) {return b ? gcd(b, a % b) : a;}
ll lcm(ll a, ll b) {return a * b / gcd(a, b);}
ll ceil(ll a, ll b) {return (a + b - 1) / b;}

int32_t main() {
        ios_base::sync_with_stdio(0);
        cin.tie(0);

        int n;
        cin >> n;

        vector<pair<ll, ll>> v(n + 1);

        for (int i = 1; i <= n; i ++) 
                cin >> v[i].F >> v[i].S;
        stable_sort(v.begin() + 1, v.end());

        vector<ll> ta(n + 1);
        for (int i = 1; i <= n; i ++) 
                ta[i] = ta[i - 1] + v[i].S;

        //ta[j] - v[j].F - (ta[i - 1] - v[i].F)
        //ta[j] - v[j].F -> const
        //(ta[i - 1] - v[i].F) -> Hay que minimizarlo 
        //
        //sum - (v[j].F - v[i].F)
        //sum -v[j].F + v[i].F
        //ta[j] - ta[i - 1] - v[j].F + v[i].F
        //ta[j] - v[j] - ta[i - 1] + v[i].F
        //(ta[j] - v[j]) - (ta[i - 1] - v[i].F) 

        ll ans = 0, mi = v[1].F;
        for (int i = 1; i <= n; i ++) {
                mi = min(mi, ta[i - 1] - v[i].F);
                ans = max(ans, ta[i] - v[i].F - mi);
        } 

        cout << ans << "\n";

        return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 20 / 20
• Subtask 4: 50 / 50