Submission #1116779

#TimeUsernameProblemLanguageResultExecution timeMemory
1116779SalihSahinShortcut (IOI16_shortcut)C++14
31 / 100
2059 ms508 KiB
#include <bits/stdc++.h>
#define pb push_back
using namespace std;
#include "shortcut.h"

long long inf = 1e16;

 
long long find_shortcut(int n, vector<int> l, vector<int> d, int c){
    vector<long long> pre(n);
    for(int i = 0; i < n-1; i++){
        pre[i+1] = pre[i] + l[i];
    }
    vector<long long> lfar(n), rfar(n);
    lfar[0] = d[0];
    for(int i = 1; i < n; i++){
        if(d[i] > lfar[i-1] + l[i-1]) lfar[i] = d[i];
        else lfar[i] = lfar[i-1] + l[i-1];
    }
    rfar[n-1] = d[n-1];
    for(int i = n-2; i >= 0; i--){
        if(d[i] > rfar[i+1] + l[i]) rfar[i] = d[i];
        else rfar[i] = rfar[i+1] + l[i];
    }
 
    vector<long long> precalcl(n), precalcr(n);
    for(int i = 1; i < n; i++){
        precalcl[i] = max(precalcl[i-1], (long long)(lfar[i-1] + l[i-1] + d[i]));
    }
    for(int i = n-2; i >= 0; i--){
        precalcr[i] = max(precalcr[i+1], (long long)(rfar[i+1] + l[i] + d[i]));
    }
 
    long long ans = inf;
 
    for(int l = 0; l < n; l++){
        long long maxla = precalcl[l];

        for(int r = l+1; r < n; r++){
            long long dis1 = 0, dis2 = 0;
            dis1 = lfar[l] + rfar[r] + min((long long)c, pre[r] - pre[l]); // L-R
            dis1 = max(dis1, precalcr[r]); // R-R
            long long clen = pre[r] - pre[l] + c;
            
            for(int j = l+1; j <= r; j++){
                dis2 = max(dis2, lfar[l] + (long long)d[j] + min(pre[j] - pre[l], clen - (pre[j] - pre[l])));
            } // L-M
            for(int j = l; j < r; j++){
                dis2 = max(dis2, rfar[r] + (long long)d[j] + min(pre[r] - pre[j], clen - (pre[r] - pre[j])));
            } // R-M
 
            for(int j = l+1; j < r; j++){ // M-M
                long long addj = d[j];
                for(int j2 = j+1; j2 < r; j2++){
                    long long addj2 = d[j2];
                    dis2 = max(dis2, min(pre[j2] - pre[j], clen - (pre[j2] - pre[j])) + addj + addj2);
                }
            }
 
            ans = min(ans, max({maxla, dis1, dis2}));
        }
    }
 
    return ans;
}
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