# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
1116560 | ortsac | COVID tests (CEOI24_covid) | C++17 | 7060 ms | 508 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
//#pragma GCC optimize("O3")
#include <bits/stdc++.h>
using namespace std;
/// You may use:
// The number of students
int N;
int eQtd, eAparece;
// The probability any given student is positive
double P;
// This function performs a test on a subset of samples.
// Its argument is a vector of Booleans of length N,
// where the i-th element is true if the i-th sample should be added to the mix.
// It returns true if (and only if) at least one of the samples in the mix is positive.
bool test_students(const std::vector<bool>& mask) {
assert(mask.size() == (size_t)N);
std::string mask_str(N, ' ');
for (int i = 0; i < N; i++)
mask_str[i] = mask[i] ? '1' : '0';
printf("Q %s\n", mask_str.c_str());
fflush(stdout);
char answer;
scanf(" %c", &answer);
return answer == 'P';
}
/// You should implement:
// This function will be called once for each test instance.
// It should use test_students to determine which samples are positive.
// It must return a vector of Booleans of length N,
// where the i-th element is true if and only if the i-th sample is positive.
vector<bool> find_positive1() {
int n = N;
vector<bool> answer(n);
int qtd = 0;
int curr = -1;
while (curr < (n - 1)) {
//if (qtd >= eQtd) {
// vector<bool> mask(n);
// for (int i = curr + 1; i < n; i++) mask[i] = 1;
// if (!test_students(mask)) break;
//}
int l = curr + 1, r = n - 1, ans = n;
while (l <= r) {
int m1 = (l + eAparece);
int m2 = (l + r)/2;
int m = min(m1, m2);
vector<bool> mask(n);
for (int i = curr + 1; i <= m; i++) mask[i] = 1;
if (test_students(mask)) {
ans = m;
r = m - 1;
} else {
l = m + 1;
}
}
curr = ans;
if (curr != n) answer[curr] = 1;
qtd++;
}
return answer;
}
vector<bool> find_positive2() {
int n = N;
vector<bool> answer(n);
int qtd = 0;
int curr = -1;
while (curr < (n - 1)) {
if (qtd >= eQtd) {
vector<bool> mask(n);
for (int i = curr + 1; i < n; i++) mask[i] = 1;
if (!test_students(mask)) break;
}
int l = curr + 1, r = n - 1, ans = n;
while (l <= r) {
int m1 = (l + eAparece);
int m2 = (l + r)/2;
int m = min(m1, m2);
vector<bool> mask(n);
for (int i = curr + 1; i <= m; i++) mask[i] = 1;
if (test_students(mask)) {
ans = m;
r = m - 1;
} else {
l = m + 1;
}
}
curr = ans;
if (curr != n) answer[curr] = 1;
qtd++;
}
return answer;
}
int main() {
int T;
scanf("%d %lf %d", &N, &P, &T);
// You may perform any extra initialization here.
eQtd = (((double) N) * P);
eAparece = 0;
double pos = 1.0;
while (pos > 0.5) {
pos *= (1.0 - P);
eAparece++;
}
for (int i = 0; i < T; i++) {
std::vector<bool> answer;
if (P > 0.02) answer = find_positive1();
else answer = find_positive2();
assert(answer.size() == (size_t)N);
std::string answer_str(N, ' ');
for (int j = 0; j < N; j++)
answer_str[j] = answer[j] ? '1' : '0';
printf("A %s\n", answer_str.c_str());
fflush(stdout);
char verdict;
scanf(" %c", &verdict);
if (verdict == 'W')
exit(0);
}
return 0;
}
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