Submission #1114829

#	Time	Username	Problem	Language	Result	Execution time	Memory
1114829		kokoue	Connecting Supertrees (IOI20_supertrees)	C++14	11 / 100	161 ms	22092 KiB

supertrees

#include<bits/stdc++.h>
#include "supertrees.h"
#define maxn 1010
#define f first
#define s second
using namespace std;
int is[maxn];
vector<pair<int,int>> comp[maxn];
int par[maxn];
int findd(int u)
{
    if(par[u]==-1) return u;
    return par[u]=findd(par[u]);
}
void unite(int u,int v)
{
    u=findd(u);
    v=findd(v);
    if(v==u) return;
    if(comp[u].size()<comp[v].size()) swap(u,v);
    for(auto e:comp[v]) comp[u].push_back(e);
    par[v]=u;
    comp[v].clear();
}
vector<vector<int>> d;
int construct(vector<vector<int>> p)
{
    int n=p.size();
    for(int i=0;i<n;i++)
    {
        par[i]=-1;
        int cntr=0;
        vector<int> dumbbb(n,0);
        d.push_back(dumbbb);
        for(auto e:p[i])
        {
            if(e==1) cntr++;
        }
        is[i]=1;

        if(cntr==1) is[i]=2;
        comp[i].push_back({is[i],i});
    }
    for(int i=0;i<n;i++)
    {
        for(int j=i+1;j<n;j++)
        {
            if(p[i][j]) unite(i,j);
        }
    }
    for(int i=0;i<n;i++)
    {
        if(comp[i].size()==0 || comp[i].size()==1) continue;
       // printf("for %d is %d\n",i,comp[i].size());
        sort(comp[i].begin(),comp[i].end());
      //  reverse(comp[i].begin(),comp[i].end());
        int prev=-1;
        int last=-1;
     //   printf("for %d: \n");
        for(auto e:comp[i])
        {
          //  printf(" {%d,%d}, ",e.f,e.s);
            if(e.f==1) last=e.s;

            if(prev==-1)
            {
                prev=e.s;

                continue;

            }

            d[prev][e.s]=1;
            d[e.s][prev]=1;
        }
        if(comp[i][comp[i].size()-1].f==1) continue;
        if(last==-1)
        {
            d[comp[i][comp[i].size()-1].s] [comp[i][0].s]=1;
            d[comp[i][0].s] [comp[i][comp[i].size()-1].s]=1;
        }
        else
        {
            d[comp[i][comp[i].size()-1].s] [last]=1;
            d[last] [comp[i][comp[i].size()-1].s]=1;
        }
    }

    build(d);
    return 1;
}

• Subtask 1: 11 / 11
• Subtask 2: 0 / 10
• Subtask 3: 0 / 19
• Subtask 4: 0 / 35
• Subtask 5: 0 / 21
• Subtask 6: 0 / 4