Submission #1114297

#	Time	Username	Problem	Language	Result	Execution time	Memory
1114297		adaawf	Cyberland (APIO23_cyberland)	C++17	15 / 100	3064 ms	44268 KiB

cyberland

#include <iostream>
#include <vector>
#include <queue>
#include <iomanip>
using namespace std;
vector<pair<int, int>> g[100005];
double f[100005][35], d[100005][35];
double solve(int n, int m, int k, int h, vector<int> x, vector<int> y, vector<int> c, vector<int> a) {
    vector<int> v, vv;
    for (int i = 0; i < n; i++) g[i].clear();
    for (int i = 0; i < n; i++) {
        if (a[i] == 0) v.push_back(i);
        if (a[i] == 2) vv.push_back(i);
        for (int j = 0; j <= k; j++) {
            f[i][j] = 1e18;
        }
    }
    for (int i = 0; i < m; i++) {
        g[x[i]].push_back({y[i], c[i]});
        g[y[i]].push_back({x[i], c[i]});
    }
    for (int w : v) f[w][0] = 0;
    f[0][0] = 0;
    for (int i = 0; i <= k; i++) {
        priority_queue<pair<double, int>> q;
        if (i != 0) {
            for (int j = 0; j < n; j++) {
                for (auto w : g[j]) {
                    if (w.first == h) continue;
                    f[j][i] = min(d[w.first][i] + w.second, f[j][i]);
                }
                //cout << j << " " << i << " " << f[j][i] << '\n';
            }
        }
        for (int j = 0; j < n; j++) {
            if (j != h) {
                q.push({-f[j][i], j});
            }
        }
        while (!q.empty()) {
            double x = -q.top().first;
            int u = q.top().second;
            q.pop();
            if (f[u][i] != x || u == h) continue;
            //cout << u << " " << i << " " << x << " 328762836" << '\n';
            for (auto w : g[u]) {
                if (f[w.first][i] > f[u][i] + w.second) {
                    f[w.first][i] = f[u][i] + w.second;
                    q.push({-f[w.first][i], w.first});
                }
            }
        }
        if (i == k) break;
        for (int j = 0; j < n; j++) {
            if (a[j] <= 1) d[j][i + 1] = f[j][i];
            else if (a[j] == 2) d[j][i + 1] = f[j][i] / 2;
        }
    }
    double res = 1e18;
    for (int j = 0; j <= k; j++) {
        res = min(res, f[h][j]);
    }
    if (res > 1e17) return -1;
    return res;
}

• Subtask 1: 0 / 5
• Subtask 2: 8 / 8
• Subtask 3: 0 / 13
• Subtask 4: 0 / 19
• Subtask 5: 7 / 7
• Subtask 6: 0 / 16
• Subtask 7: 0 / 29
• Subtask 8: 0 / 3