Submission #1113937

#	Time	Username	Problem	Language	Result	Execution time	Memory
1113937		lucascgar	Cyberland (APIO23_cyberland)	C++17	15 / 100	3035 ms	65708 KiB

cyberland

#include <bits/stdc++.h>

using namespace std;

/*

*/

typedef pair<int, int> pii;
typedef pair<long long, long long> pll;
typedef pair<long double, long double> pdd;

const int MAXN = 1e5+10, MAXK = 30+15;
const long long BIG = 1e18+8;

const long double PRECISION = 1e-7;

vector<pii> e[MAXN];

long double ds[MAXN][MAXK];

bool r[MAXN];

void dfs(int x){
    r[x] = 1;
    for (auto &[i,cst]:e[x]) if (!r[i]) dfs(i);
}

double solve(int n, int m, int k, int H, vector<int> x, vector<int> y, vector<int> c, vector<int> arr){

    for (int i=0;i<n;i++){
        e[i].clear();
        for (int j=0;j<=k;j++) ds[i][j]=BIG;
        r[i] = 0;
    }

    for (int i=0;i<m;i++){
        int a = x[i], b = y[i];
        e[a].emplace_back(b, c[i]);
        e[b].emplace_back(a,c[i]);
    }
    dfs(0);
    typedef tuple<long double, int, int> node;  // {dst, qntk, u}
    priority_queue<node, vector<node>, greater<>> q;
    for (int i=0;i<n;i++) if (!i || (r[i] && arr[i]==0)){
        ds[i][0] = 0;
        q.emplace(0, 0, i);
    }

    while (!q.empty()){
        auto [d, qk, u] = q.top();
        q.pop();
        if (ds[u][qk] != d) continue;

        if (u == H) continue;

        for (auto &[i, cs]:e[u]){
            long double nc = d+cs;
            // sem usar
            if (ds[i][qk]>nc){
                ds[i][qk] = nc;
                q.emplace(nc, qk, i);
            }

            // usando
            if (qk<k && arr[u] == 2 && ds[i][qk+1]> (d/2.000+cs)){
                ds[i][qk+1] = d/2.00 + cs;
                q.emplace(ds[i][qk+1], qk+1, i);
            }
        }
    }
    long double ans = BIG;
    for (int i=0;i<=k;i++) ans = min(ans, ds[H][i]);
    if (ans == BIG) return -1;
    return ans;

}

• Subtask 1: 0 / 5
• Subtask 2: 8 / 8
• Subtask 3: 0 / 13
• Subtask 4: 0 / 19
• Subtask 5: 7 / 7
• Subtask 6: 0 / 16
• Subtask 7: 0 / 29
• Subtask 8: 0 / 3