This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
#define int long long
#define pb push_back
#define fast ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
#define MOD 1000000007
#define inf 1e18
#define fi first
#define se second
#define FOR(i,a,b) for(int i=a;i<=b;i++)
#define FORD(i,a,b) for(int i=a;i>=b;i--)
#define sz(a) ((int)(a).size())
#define endl '\n'
#define pi 3.14159265359
#define TASKNAME "divteam"
using namespace std;
template<typename T> bool maximize(T &res, const T &val) { if (res < val){ res = val; return true; }; return false; }
template<typename T> bool minimize(T &res, const T &val) { if (res > val){ res = val; return true; }; return false; }
typedef pair<int,int> ii;
typedef pair<int,ii> iii;
typedef vector<int> vi;
/**
Ta có thể dễ dàng tính được số team nhiều nhất bằng dp thông thường.
Bây giờ ta cần kiểm soát kích thước của tập lớn nhất.
Giả sử tập lớn nhất là mid.
dp_i = dp_j + 1 (j thuộc [i - mid, i - a[i] ].
Ta nhận thấy rằng là i - mid sẽ tăng dần, trong khi i - a[j] sẽ giảm dần.
Mình có thể dùng deque ko nhỉ.
**/
const int MAXN = 1e6 + 10;
vector<ii> query[MAXN];
ii ord[MAXN];
int n;
int dp[MAXN], trace[MAXN], mx = 0;
int lab[MAXN], realLeader[MAXN];
int root(int u){
if (lab[u] < 0) return u;
else return lab[u] = root(lab[u]);
}
void unite(int u, int v){
u = root(u);
v = root(v);
if (u != v){
int newLeader = realLeader[v];
if (lab[u] > lab[v]) swap(u, v);
lab[u] += lab[v];
lab[v] = u;
realLeader[u] = newLeader;
}
}
int get(int id){
int x = root(id);
return realLeader[x];
}
vector<int> stk;
bool check(int mid){
memset(dp, -0x3f, sizeof(dp));
dp[0] = 0;
FOR(i, 0, n){
realLeader[i] = i;
lab[i] = -1;
}
FOR(i, 1, n){
if (i - ord[i].fi >= 0) query[i - ord[i].fi].pb({max(0LL, i - mid), i});
}
while(!stk.empty()) stk.pop_back();
FOR(i, 0, n){
if (stk.empty()) stk.pb(i);
else{
while(stk.size() > 0 and dp[stk.back()] < dp[i]){
unite(stk.back(), i);
stk.pop_back();
}
stk.pb(i);
}
for(auto p: query[i]){
int l = p.fi;
int id = p.se;
// cout << l << ' ' << i << ' ' << id << ' ' << ' ' << D.root(l) << endl;
dp[id] = dp[get(l)] + 1;
trace[id] = get(l);
}
}
FOR(i, 1, n){
if (i - ord[i].fi >= 0) query[i - ord[i].fi].pop_back();
}
return dp[n] == mx;
}
void traced(int s){
queue<int> q;
q.push(s);
while(!q.empty()){
int x = q.front();
q.pop();
int tr = trace[x];
cout << x - tr << ' ';
FOR(i, tr + 1, x){
cout << ord[i].se << ' ';
}
cout << endl;
if (tr != 0) q.push(tr);
}
}
main()
{
fast;
if (fopen(TASKNAME".inp","r")){
freopen(TASKNAME".inp","r",stdin);
freopen(TASKNAME".out","w",stdout);
}
cin >> n;
int mxA = 0;
FOR(i, 1, n){
cin >> ord[i].fi;
ord[i].se = i;
maximize(mxA, ord[i].fi);
}
sort(ord + 1, ord + 1 + n);
check(n + 1);
mx = dp[n];
int l = mxA, r = n, res = -1;
while(l <= r){
int mid = (l + r) >> 1;
if (check(mid)){
res = mid;
r = mid - 1;
}
else{
l = mid + 1;
}
}
check(res);
cout << mx << endl;
traced(n);
}
/**
Warning:
Đọc sai đề???
Cận lmao
Code imple thiếu case nào không.
Limit.
**/
Compilation message (stderr)
tea.cpp:121:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
121 | main()
| ^~~~
tea.cpp: In function 'int main()':
tea.cpp:125:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
125 | freopen(TASKNAME".inp","r",stdin);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~
tea.cpp:126:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
126 | freopen(TASKNAME".out","w",stdout);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~
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