This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef pair<int, int> pii;
const int MAXN = 1e6 + 5;
int N, K, Q, T;
// Tree information
int P[2][MAXN], root[2];
vector<int> child[2][MAXN];
vector<int> ord[2];
int tin[2][MAXN], tout[2][MAXN], depth[2][MAXN];
int subtree_by_ord[MAXN];
pii init_tree[2 * MAXN];
pii tree[8 * MAXN];
// Initialize all arrays to avoid undefined behavior
void initializeArrays() {
fill_n(&P[0][0], 2 * MAXN, -1);
fill_n(&root[0], 2, -1);
for (int i = 0; i < 2; ++i) {
ord[i].clear();
fill_n(&tin[i][0], MAXN, 0);
fill_n(&tout[i][0], MAXN, 0);
fill_n(&depth[i][0], MAXN, 0);
child[i]->clear();
}
fill_n(subtree_by_ord, MAXN, 0);
fill_n(&init_tree[0], 2 * MAXN, make_pair(INT_MAX, INT_MAX));
fill_n(&tree[0], 8 * MAXN, make_pair(INT_MAX, INT_MAX));
}
// Iterative DFS to avoid stack overflow
void dfs(int curtree, int start) {
stack<pair<int, int>> stk; // Pair of node and DFS state
stk.push({start, 0});
int cte = 0;
while (!stk.empty()) {
auto [u, state] = stk.top();
stk.pop();
if (state == 0) {
tin[curtree][u] = ++cte;
ord[curtree].push_back(u);
if (curtree == 0) init_tree[cte] = make_pair(depth[curtree][u], u);
stk.push({u, 1}); // Add state 1 for postorder actions
for (int v : child[curtree][u]) {
depth[curtree][v] = depth[curtree][u] + 1;
stk.push({v, 0}); // Add children with state 0
}
} else {
tout[curtree][u] = cte;
if (curtree == 0) init_tree[++cte] = make_pair(depth[curtree][u], u);
}
}
}
// Utility function to find minimum of two pairs
pii min_pair(const pii &a, const pii &b) {
if (a.first < b.first || (a.first == b.first && a.second < b.second)) return a;
return b;
}
// Build the segment tree
void build(int node, int start, int end) {
if (start == end) {
tree[node] = init_tree[start];
} else {
int mid = (start + end) / 2;
build(2 * node, start, mid);
build(2 * node + 1, mid + 1, end);
tree[node] = min_pair(tree[2 * node], tree[2 * node + 1]);
}
}
// Query the minimum in range [L, R]
pii qry(int node, int start, int end, int L, int R) {
if (R < start || end < L) {
return {INT_MAX, INT_MAX}; // return max pair (acts as neutral for min)
}
if (L <= start && end <= R) {
return tree[node];
}
int mid = (start + end) / 2;
pii left_min = qry(2 * node, start, mid, L, R);
pii right_min = qry(2 * node + 1, mid + 1, end, L, R);
return min_pair(left_min, right_min);
}
int lca(int curtree, int u, int v) {
int l = tin[curtree][u], r = tin[curtree][v];
if (l > r) swap(l, r);
return qry(1, 1, 2 * N, l, r).second;
}
bool sort_by_ord1(int u, int v) {
return tin[1][u] < tin[1][v];
}
// Answer recovery
int result[2][MAXN][2];
// Equation graph for tree 1
int distdata[MAXN];
vector<pii> recov_edge[MAXN];
void recover_dfs(int u) {
for (auto [v, w] : recov_edge[u]) {
if (distdata[v] == -1) {
distdata[v] = distdata[u] + w;
recover_dfs(v);
}
}
}
// Euler tour quicksum for tree 2
int qc[3 * MAXN];
int qc2[3 * MAXN];
// Queries
int query[MAXN][2];
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
initializeArrays(); // Ensure all arrays are initialized to avoid segmentation faults
cin >> N >> K >> Q >> T;
for (int i = 1; i <= N; i++) cin >> P[0][i];
for (int i = 1; i <= N; i++) cin >> P[1][i];
for (int i = 1; i <= N; i++) {
if (P[0][i] != -1) child[0][P[0][i]].push_back(i);
else root[0] = i;
if (P[1][i] != -1) child[1][P[1][i]].push_back(i);
else root[1] = i;
}
ord[0].push_back(0);
ord[1].push_back(1);
depth[0][root[0]] = depth[1][root[1]] = 0;
dfs(0, root[0]);
dfs(1, root[1]);
build(1, 1, 2 * N);
for (int i = 1; i <= K; i++) subtree_by_ord[i] = ord[0][i];
sort(subtree_by_ord + 1, subtree_by_ord + K + 1, sort_by_ord1);
// Query and results processing
for (int i = 1; i <= T; i++) {
int u = query[i][0], v = query[i][1];
int uvlca = lca(0, u, v);
cout << distdata[u] + distdata[v] - 2 * distdata[uvlca] << ' ';
if (tin[1][u] > tin[1][v]) swap(u, v);
if (tin[1][v] < tout[1][u])
cout << qc[tin[1][v]] - qc[tin[1][u]] << '\n';
else
cout << qc[tin[1][v]] - qc2[tout[1][u]] << '\n';
}
return 0;
}
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