Submission #1109100

#	Time	Username	Problem	Language	Result	Execution time	Memory
1109100		Ryu	Pohlepko (COCI16_pohlepko)	C++17	10 / 80	1092 ms	65536 KiB

pohlepko

#include <bits/stdc++.h>
#define F first
#define S second
#define LL long long

#define rep(i, x) for(auto &i : (x))
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()

#define left(x) ((x)<<1)
#define right(x) ((x)>>1)
#define LSOne(x) (x & -(x))

using namespace std;
using T = pair<char, pair<int, int>>;

const int SZ = 2e5 + 1;
const LL MOD = 1e9 + 7; 
const LL INF = 1e18 + 1;

LL bp (LL b, LL e, LL m = MOD) {
 if ( e == 0 ) return 1;
 LL T = bp(b, e / 2);
 T *= T; T %= m;
 if ( e & 1 ) T *= b;
 return T %= m;
}

LL nv_i (LL a) { return bp(a, MOD - 2); };
LL gcd (LL a, LL b) { return (b == 0 ? a : gcd(b, a % b)); }
LL lcm(LL a, LL b) { return (a * (b / gcd(a, b))); }
LL ceil (LL a, LL b) { return ((a + b - 1) / b); }

vector<vector<char>> G;
vector<vector<bool>> VIS;
vector<vector<pair<int, int>>> FATHER;
int n, m;

void dijkstra() {
    priority_queue<T, vector<T>, greater<T>> PQ;

    PQ.push({G[1][1], {1, 1}});

    while(!PQ.empty()) {
      int i = PQ.top().S.F, j = PQ.top().S.S;
      char letter = PQ.top().F;
      PQ.pop();

      pair<int, int> a = {0, 0};

      if(i + 1 <= n) {
        PQ.push({G[i + 1][j], {i + 1, j}});

        if(FATHER[i + 1][j] != a) {
          a = FATHER[i + 1][j];

          if(letter <= G[a.F][a.S]) {
            FATHER[i + 1][j] = {i, j};
          }
        }
        else {
          FATHER[i + 1][j] = {i, j};
        }
        a = {0, 0};
      }
    
      if(j + 1 <= m) {
        PQ.push({G[i][j + 1], {i, j + 1}});

        if(FATHER[i][j + 1] != a) {
          a = FATHER[i][j + 1];

          if(letter <= G[a.F][a.S]) {
            FATHER[i][j + 1] = {i, j};
          }
        }
        else {
          FATHER[i][j + 1] = {i, j};
        }
        a = {0, 0};
      }
    }
}

void word(int i, int j) {
  if(i == 1 && j == 1) {
    cout << char(G[i][j]);
    return;
  }
  word(FATHER[i][j].F, FATHER[i][j].S);
  cout << char(G[i][j]);
}

void solve() {
  cin >> n >> m;

  G.resize(n + 1, vector<char> (m + 1));
  VIS.resize(n + 1, vector<bool> (m + 1));
  FATHER.resize(n + 1, vector<pair<int, int>> (m + 1));

  for(int i = 1; i <= n; i ++) {
    for(int j = 1; j <= m; j ++) {
      cin >> G[i][j];
    }
  }
   
  dijkstra();

  word(n, m);
}

signed main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0), cout.tie(0);

  solve();
  return 0;
}

• Subtask 1: 10 / 80