Submission #1108911

#TimeUsernameProblemLanguageResultExecution timeMemory
1108911akim9905Copy and Paste 3 (JOI22_copypaste3)C++17
20 / 100
403 ms134088 KiB
#include <bits/stdc++.h> using namespace std; #define fileio() freopen("input.txt","r",stdin); freopen("output.txt","w",stdout) #define fio() ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) #define all(x) (x).begin(), (x).end() #define allr(x) x.rbegin(), x.rend() #define cmprs(x) sort(all(x)),x.erase(unique(all(x)),x.end()) #define endl "\n" #define sp " " #define pb push_back #define lb lower_bound #define ub upper_bound #define rz resize #define sz(a) (int)(a.size()) #define clr(a) a.clear() typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; typedef pair<int, ll> pil; typedef tuple<int, int, int> tpi; typedef tuple<ll, ll, ll> tpl; typedef pair<double, ll> pdl; typedef pair<double, int> pdi; const int dx[] = {1,-1,0,0,1,1,-1,-1}; const int dy[] = {0,0,1,-1,1,-1,1,-1}; const ll MOD = 1e9+7; const int INF = 0x3f3f3f3f; const ll LINF = 0x3f3f3f3f3f3f3f3f; const int MAX = 2525; // PLZ CHK! template <ll P, ll M> struct Hash { vector<ll> H,B; void build(const string &S) { H.resize(sz(S)+1), B.resize(sz(S)+1); B[0]=1; for (int i=1; i<=sz(S); i++) H[i]=(H[i-1]*P+S[i-1])%M; for (int i=1; i<=sz(S); i++) B[i]=B[i-1]*P%M; } ll get(int s, int e) { return (H[e]-H[s-1]*B[e-s+1]%M+M)%M; } }; Hash<1299709, 1'000'000'007> H; int N; ll A,B,C,D[MAX][MAX],I[MAX][MAX]; string S; int main() { fio(); cin>>N>>S>>A>>B>>C; H.build(S); S=' '+S; map<ll,vector<pii>> idx; for (int i=1; i<=N; i++) { for (int j=i; j<=N; j++) { idx[H.get(i,j)].pb({i,j}); } } fill_n(&I[0][0],MAX*MAX,LINF); for (auto &[t,v]:idx) { for (int i=0; i<sz(v); i++) { auto [s,e]=v[i]; int t=lb(all(v),pii{e+1,-1})-v.begin(); if (t<sz(v)) I[s][e]=v[t].first; } } fill_n(&D[0][0],MAX*MAX,LINF); for (int i=1; i<=N; i++) D[i][i]=A+B; for (int i=1; i<=N; i++) { for (int l=1,r=l+i-1; r<=N; l++,r++) { if (l>1) D[l-1][r]=min(D[l-1][r], A+D[l][r]); if (r<N) D[l][r+1]=min(D[l][r+1], A+D[l][r]); int cur=I[l][r], cnt=2; while (cur+i-1<=N) { D[l][cur+i-1]=min(D[l][cur+i-1], D[l][r]+C*cnt+A*(cur+i-l-cnt*i)+B); cnt++,cur=I[cur][cur+i-1]; } } } cout<<D[1][N]-B; return 0; }
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