Submission #1108611

#	Time	Username	Problem	Language	Result	Execution time	Memory
1108611		kyaruru	Fish (IOI08_fish)	C++17	75 / 100	274 ms	30152 KiB

fish

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);

    int a, b, c;
    cin >> a >> b >> c;
    pll k[a + 1];
    for (int i = 1; i <= a; i++) {
        ll x, y;
        cin >> x >> y;
        k[i] = {x, y};
    }

    int h = ceil(log2(b));
    int n = (1 << h) - 1;
    vector<ll> seg(1 << (h + 1), 1), sega(1 << (h + 1), 1);

    sort(k + 1, k + a + 1);

    ll ed[b + 1], sv[b + 1], u[b + 1];
    memset(ed, -1, sizeof(ed));
    memset(u, -1, sizeof(u));
    memset(sv, 0, sizeof(sv));

    int m = b;
    for (int i = a; i >= 1; i--) {
        if (ed[k[i].second] == -1) ed[k[i].second] = m--;
        k[i].second = ed[k[i].second];
    }

    vector<int> ka;
    memset(ed, -1, sizeof(ed));
    for (int i = a; i >= 1; i--) {
        if (ed[k[i].second] == -1)
            ed[k[i].second] = i, ka.push_back(k[i].first);
        else if (2 * k[i].first > k[ed[k[i].second]].first)
            u[k[i].second] = k[i].first;
    }

    sort(ka.begin(), ka.end());
    ll r = 1, ans = 0;
    for (int i = 1; i <= a; i++) {
        while (2 * k[r].first <= k[i].first) {
            if (ed[k[r].second] < i) {
                int j = k[r].second + n;
                seg[j]++;
                for (j /= 2; j >= 1; j /= 2) seg[j] = seg[2 * j] * seg[2 * j + 1] % c;
            } else
                sv[k[r].second]++;

            int j = k[r].second + n;
            sega[j]++;
            for (j /= 2; j >= 1; j /= 2) sega[j] = sega[2 * j] * sega[2 * j + 1] % c;
            r++;
        }
        if (ed[k[i].second] == i) {
            int j = k[i].second + n;
            seg[j] += sv[k[i].second];
            for (j /= 2; j >= 1; j /= 2) seg[j] = seg[2 * j] * seg[2 * j + 1] % c;
            ans += seg[1];

            j = k[i].second + n;
            ll p = sega[j];
            sega[j] = seg[j] = 1;
            for (j /= 2; j >= 1; j /= 2) {
                sega[j] = sega[2 * j] * sega[2 * j + 1] % c;
                seg[j] = seg[2 * j] * seg[2 * j + 1] % c;
            }

            int v = u[k[i].second] == -1 ? b : lower_bound(ka.begin(), ka.end(), 2 * u[k[i].second]) - ka.begin();
            ll l = 1 + n, r = v + n, t = 1, tt = 1;
            while (l <= r) {
                if (l % 2 == 1) {
                    t = t * sega[l] % c;
                    tt = tt * seg[l] % c;
                    l++;
                }
                if (r % 2 == 0) {
                    t = t * sega[r] % c;
                    tt = tt * seg[r] % c;
                    r--;
                }
                l /= 2, r /= 2;
            }
            ans += t - tt;

            j = k[i].second + n;
            sega[j] = seg[j] = p;
            for (j /= 2; j >= 1; j /= 2) {
                sega[j] = sega[2 * j] * sega[2 * j + 1] % c;
                seg[j] = seg[2 * j] * seg[2 * j + 1] % c;
            }
        }
    }

    cout << (ans % c + c) % c;
}

• Subtask 1: 4 / 4
• Subtask 2: 4 / 4
• Subtask 3: 4 / 4
• Subtask 4: 0 / 4
• Subtask 5: 4 / 4
• Subtask 6: 5 / 5
• Subtask 7: 6 / 6
• Subtask 8: 6 / 6
• Subtask 9: 6 / 6
• Subtask 10: 0 / 6
• Subtask 11: 7 / 7
• Subtask 12: 7 / 7
• Subtask 13: 7 / 7
• Subtask 14: 5 / 5
• Subtask 15: 5 / 5
• Subtask 16: 5 / 5
• Subtask 17: 0 / 5
• Subtask 18: 0 / 5
• Subtask 19: 0 / 5