# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
1108101 | laight | Tropical Garden (IOI11_garden) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "garden.h"
#include "gardenlib.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#define pi pair<int, int>
#define fi first
#define se second
#define ll long long
#define ull unsigned long long
#define ld long double
#define pb push_back
#define mp make_pair
#define pll pair<ll, ll>
#define umi unordered_map<int, int>
#define umll unordered_map<ll, ll>
#define umllv unordered_map<ll, vector<ll>>
#define getchar() (*_pinp?*_pinp++:(_inp[fread(_pinp=_inp, 1, 4096, stdin)]='\0', *_pinp++))
char _inp[4097], *_pinp=_inp;
#define scan(x) do{while((x=getchar())<'-'); _ssign=x=='-'; if(_ssign) while((x=getchar())<'0'); for(x-='0'; '0'<=(_=getchar()); x=(x<<3)+(x<<1)+_-'0'); x=_ssign?-x:x;}while(0)
char _; bool _ssign;
// #pragma GCC optimize("Ofast")
// #pragma GCC target("avx2")
using namespace std; using namespace __gnu_pbds;
const int MM = 1e5+5e4+5;
const ll inf = 2e15+1;
const int lg = 17; // 17 for 1e5, 31 for 1e9
int n, m, p, a, b, dis[2*MM], dis2[2*MM], lv, cycl, cl1, cl2, q, inp; bool cvis[2*MM], vis[2*MM], vis2[2*MM], hcy, cy1, cy2;
vector<int> g(2005), ans(2005), to(2*MM), rev[2*MM], graph[MM];
void g_f(int c, int d){
if (vis[c]) return;
vis[c] = 1; dis[c] = d;
for (int i : rev[c]){
g_f(i, d+1);
}
}
void g_f2(int c, int d){
if (vis2[c]) return;
vis2[c] = 1; dis2[c] = d;
for (int i : rev[c]){
g_f2(i, d+1);
}
}
void cyc_f(int c, int d, int pe){
if (cvis[c]){
if (c == pe) {hcy = 1; cycl = d;}
return;
}
cvis[c] = 1; cyc_f(to[c], d+1, pe);
}
void count_routes(int N, int M, int P, int R[][2], int Q, int G[]){
// cin.tie(0); cin.sync_with_stdio(0);
// freopen("changyue_tst.txt", "r", stdin);
n = N; m = M; p = P;
for (int i=0; i<m; ++i){
graph[R[i][0]].pb(R[i][1]); graph[R[i][1]].pb(R[i][0]);
}
q = Q; for (int i=0; i<q; i++) {g[i] = G[i];}
for (int i=0; i<n; ++i){
int oth = graph[i][0];
if (i == graph[oth][0]){
to[i] = n+oth;
}
else {to[i] = oth;}
if (graph[i].size() >= 2){
int oth2 = graph[i][1];
if (i == graph[oth2][0]){
to[n+i] = n+oth2;
}
else {to[n+i] = oth2;}
}
else{
if (i == graph[oth][0]){
to[n+i] = n+oth;
}
else {to[n+i] = oth;}
}
}
for (int i=0; i<2*n; i++){
rev[to[i]].pb(i);
}
hcy = 0; cycl = 0;
cyc_f(p, 0, p);
cl1 = cycl; cy1 = hcy;
memset(cvis, 0, sizeof(cvis));
hcy = 0; cycl = 0;
cyc_f(n+p, 0, n+p);
cl2 = cycl; cy2 = hcy;
g_f(p, 0); g_f2(n+p, 0);
for (int i=0; i<q; ++i){
int tv=g[i], ca=0;
for (int j=0; j<n; ++j){
int addon=0;
if (cy1 && vis[j]){
if (tv >= dis[j] && (tv%cl1 == dis[j]%cl1)){
addon = 1;
}
}
else if (vis[j){
if (tv == dis[j]) addon = 1;
}
if (cy2 && vis2[j]){
if (tv >= dis2[j] && (tv%cl2 == dis2[j]%cl2)){
addon = 1;
}
}
else if (vis2[j]){
if (tv == dis2[j]) addon = 1;
}
ca += addon;
}
answer(ca);
}
}