Submission #1106357

#TimeUsernameProblemLanguageResultExecution timeMemory
1106357azberjibiouBit Shift Registers (IOI21_registers)C++17
58 / 100
1 ms504 KiB
#include "registers.h" #include <bits/stdc++.h> using namespace std; void solv0(int n, int k ,int q){ int bit; if(n==2) bit=1; else bit=7; int tot=(1<<bit); // set 1 for a[n+1]~a[2^bit-1] vector <bool> v0(2000, false); for(int i=n*k;i<tot*k;i++) v0[i]=true; if(n!=tot){ append_store(50, v0); append_or(0, 0, 50); } for(int i=0;i<bit;i++){ vector <bool> v1(2000, false), v2(2000, false); for(int j=0;j<tot;j++){ if(j%(1<<(i+1))==0){ for(int z=j*k;z<(j+1)*k;z++) v1[z]=true; } else if(j%(1<<i)==0){ for(int z=j*k;z<(j+1)*k;z++) v2[z]=true; } } // 1: 2^(i+1)x번째 값, 2: 2^(i+1)x+2^i번째 값 append_store(51, v1); append_store(52, v2); append_move(1, 0); append_move(2, 0); append_and(1, 1, 51); append_and(2, 2, 52); append_right(2, 2, (1<<i)*k); // 3: !2, 4: 1+3의 k+1번째 자리 //!y = 2^b-1 - y // x + !y < 2^b <=> x+2^b-1-y < 2^b <=> x-y-1<0 <=> x<=y // k+1번째 자리가 0 <=> x<=y append_not(3, 2); append_and(3, 3, 51); append_add(4, 1, 3); vector <bool> v3(2000, false); for(int j=0;j<tot;j++){ if(j%(1<<(i+1))==0) v3[(j+1)*k]=true; } append_store(53, v3); append_and(4, 4, 53); append_right(4, 4, k); //5: 0 -> 1111, 1 -> 0000, 6: !5 append_add(5, 4, 51); append_and(5, 5, 51); append_not(6, 5); append_and(6, 6, 51); //0: 5&1+6&2 append_and(7, 5, 1); append_and(8, 6, 2); append_add(0, 7, 8); } } void solv1(int n, int k, int q){ //set 1 for a[n+1]~a[127] vector <bool> v0(2000, false); for(int i=n*k;i<16*k;i++) v0[i]=true; append_store(50, v0); append_or(0, 0, 50); for(int i=0;i<4;i++){ //v1: 1010..., 11001100... vector <bool> v1(2000, false); for(int j=0;j<16;j++){ if(j%(1<<(i+1))<(1<<i)) for(int z=j*k;z<(j+1)*k;z++) v1[z]=true; } append_store(51, v1); // 1: 2^(i+1)개 기준으로 앞에 절반, 2: 뒤에 절반 append_and(1, 0, 51); append_right(2, 0, k*(1<<i)); append_and(2, 2, 51); // v2: 2^i-1번째만 가져옴 vector <bool> v2(2000, false); for(int j=0;j<n;j++){ if(j%(1<<(i+1))==(1<<i)-1) for(int z=j*k;z<(j+1)*k;z++) v2[z]=true; } append_store(52, v2); //v3: 2^i-1번째의 받아올림 자리만 가져옴 vector <bool> v3(2000, false); for(int j=0;j<n;j++){ if(j%(1<<(i+1))==(1<<i)-1) v2[(j+1)*k]=true; } append_store(53, v3); //v4: 0~2^i-1번째 자리만 가져옴 vector <bool> v4(2000, false); for(int j=0;j<n;j++){ if(j%(1<<(i+1))<=(1<<i)-1) for(int z=j*k;z<(j+1)*k;z++) v2[z]=true; } append_store(54, v4); for(int j=0;j<(1<<(i+1));j++){ //3, 4: 1, 2의 중요 원소만 가져옴 append_and(3, 1, 52); append_and(4, 2, 52); //5: !4 append_not(5, 4); //6: 3+!4 append_add(6, 3, 5); //7: 3+!4의 받아올림자리 append_and(7, 6, 53); append_right(7, 7, k*(1<<i)); //8: 0 -> 1111, 1 -> 0000, 9: !8 append_add(8, 7, 54); append_and(8, 8, 54); append_not(9, 8); append_and(9, 9, 54); //x+!y<2^k => x<y+1 => max(x, y)=y //8=0000 => x+!y>=2^k => x>=y => 3 //12: 9&3+8&4 append_and(10, 9, 3); append_and(11, 8, 4); append_add(12, 10, 11); //13: 12를 자기 위치로 옮기기 append_right(13, 12, j*k); //99: 정렬 후 append_or(99, 13, 12); //14: 1을 shift, 15: 2를 shift append_left(14, 1, k); append_left(15, 2, k); //8=0000 => x>=y => 1을 shift //1=9&14+8&1 append_and(16, 9, 14); append_and(17, 8, 1); append_add(1, 16, 17); //2=8&15+9&2 append_and(18, 8, 15); append_and(19, 9, 2); append_add(2, 18, 19); } append_move(0, 99); vector <bool> v5(2000, false); append_store(99, v5); } } void construct_instructions(int s, int n, int k, int q) { if(s==0){ solv0(n, k, q); } else{ solv1(n, k, q); } }
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