Submission #1106187

#	Time	Username	Problem	Language	Result	Execution time	Memory
1106187		akim9905	Let's Win the Election (JOI22_ho_t3)	C++17	10 / 100	1069 ms	1008708 KiB

Main

#include <bits/stdc++.h>
using namespace std;

#define fileio() freopen("input.txt","r",stdin); freopen("output.txt","w",stdout)
#define fio() ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define all(x) (x).begin(), (x).end()
#define allr(x) x.rbegin(), x.rend()
#define cmprs(x) sort(all(x)),x.erase(unique(all(x)),x.end())
#define endl "\n"
#define sp " "
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define F first
#define S second
#define rz resize
#define sz(a) (int)(a.size())
#define clr(a) a.clear()

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<int, ll> pil;
typedef tuple<int, int, int> tpi;
typedef tuple<ll, ll, ll> tpl;
typedef pair<double, ll> pdl;
typedef pair<double, int> pdi;

const int dx[] = {1,-1,0,0,1,1,-1,-1};
const int dy[] = {0,0,1,-1,1,-1,1,-1};
const ll MOD = 1e9+7;
const int INF = 0x3f3f3f3f;
const ll LINF = 0x3f3f3f3f3f3f3f3f;
const int MAX = 505; // PLZ CHK!

int N,K;
pair<double,double> A[MAX];
double D[MAX][MAX][MAX];
const double eps=1e-5;

double go(int i, int j, int k) {
    if (k>=K) return 0.0;
    if (i>N) return 1e9;
    double &ret=D[i][j][k];
    if (ret>-1.0) return ret;

    ret=go(i+1,j,k);
    ret=min(ret, go(i+1,j,k+1)+A[i].first/(1.0*j));
    if (A[i].second<1e9) ret=min(ret, go(i+1,j+1,k+1)+A[i].second/(1.0*j));

    return ret;
}

int main() {
    fio();
    cin>>N>>K;
    for (int i=1; i<=N; i++) {
        cin>>A[i].first>>A[i].second;
        if (abs(A[i].second+1.0)<eps) A[i].second=1e9;
    }

    sort(A+1,A+N+1,[](auto a, auto b){
        if (abs(a.second-b.second)<eps) return a.first<b.first;
        return a.second<b.second;
    });

    fill_n(&D[0][0][0],MAX*MAX*MAX,-1.0);

    cout<<fixed; cout.precision(10);
    cout<<go(1,1,0);

    return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 0 / 11
• Subtask 4: 0 / 12
• Subtask 5: 0 / 33
• Subtask 6: 0 / 11
• Subtask 7: 0 / 23