Submission #1104753

#TimeUsernameProblemLanguageResultExecution timeMemory
1104753NaxocistTropical Garden (IOI11_garden)C++17
49 / 100
49 ms53164 KiB
#include "garden.h" #include "gardenlib.h" #include <bits/stdc++.h> using namespace std; #define pb emplace_back #define INF 2e9 const int N = 2e5 + 3; vector<int> adj[N]; int mx[N], mx2[N]; vector<int> g[2*N], rev[2*N]; int d1[2*N], d2[2*N]; bool vis[2*N]; int n, m, p; int cnt = 0; bool cycle(int u, int root) { if(vis[u]) return u == root; cnt ++; vis[u] = true; for(auto v : g[u]) { bool t = cycle(v, root); if(t) return true; } return false; } void dfs(int u, int d[]) { for(auto v : rev[u]) { if(d[v] != -1 and d[u] + 1 >= d[v]) continue ; d[v] = d[u] + 1; dfs(v, d); } } // answer (x); void count_routes(int N, int M, int P, int R[][2], int Q, int G[]) { n = N, m = M, p = P; memset(mx, -1, sizeof mx); memset(mx2, -1, sizeof mx2); for(int i=0; i<m; ++i) { int u = R[i][0], v = R[i][1]; if(mx[u] == -1) mx[u] = v; else if(mx2[u] == -1) mx2[u] = v; if(mx[v] == -1) mx[v] = u; else if(mx2[v] == -1) mx2[v] = u; adj[u].pb(v), adj[v].pb(u); } for(int u=0; u<2*n; ++u) { if(u < n) { // didn't walk through beautiful edge before u if(mx[u] == -1) continue ; int v = mx[u]; if(mx[v] == u) v += n; g[u].pb(v); }else { // walked through beautiful edge already before u int v = mx2[u - n]; if(v == -1) v = mx[u - n]; if(v == -1) continue ; if(mx[v] == u - n) v += n; g[u].pb(v); } } for(int u=0; u<2*n; ++u) { for(int v : g[u]) { rev[v].pb(u); } } int q; memset(d1, -1, sizeof d1); d1[p] = 0; dfs(p, d1); bool c = cycle(p, p); if(c) q = cnt; memset(d2, -1, sizeof d2); memset(vis, 0, sizeof vis); d2[p + n] = 0; cnt = 0; dfs(p + n, d2); bool cc = cycle(p + n, p + n); int qq = cnt; //for(int i=0; i<2*n; ++i) cout << d1[i] << ' ' ; cout << endl; //for(int i=0; i<2*n; ++i) cout << d2[i] << ' ' ; cout << endl; for(int i=0; i<Q; ++i) { int k = G[i], res = 0; for(int u=0; u<n; ++u) { bool ok = false; if(d1[u] != -1 and d1[u] <= k) { if(c) ok = (k - d1[u]) % q == 0; else ok = k == d1[u]; } if(d2[u] != -1 and d2[u] <= k) { if(cc) ok = (k - d2[u]) % qq == 0; else ok = k == d2[u]; } res += ok; } answer(res); } }
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