Submission #1104252

#	Time	Username	Problem	Language	Result	Execution time	Memory
1104252		_8_8_	Train (APIO24_train)	C++17	10 / 100	314 ms	84376 KiB

train

#include "train.h"
#include <bits/stdc++.h>

using namespace std;
typedef long long ll;

const int N = 1e5 + 12;

struct bit{
    vector<ll> t;
    int n;
    void init(int s) {
        n = s;
        t.assign(n + 1, 0);
    }
    void upd(int pos, ll val) {
        while(pos <= n) {
            t[pos] += val;
            pos += pos & -pos;    
        }
    }
    ll get(int i) {
        ll res = 0;
        while(i) {
            res += t[i];
            i -= i & -i;
        }
        return res;
    }
    ll get(int l, int r) {
        return get(r) - get(l - 1);
    }
}T;
int n, m, w, it = 0, ti = 0;
vector<int> t, x, y, a, b, c, vt;
vector<pair<int, int>> f;
struct qwq{ 
    int pos;
    ll d;
    int l, r, v;
};
deque<qwq> d[N];
ll dp[N];

int col = 0;
const ll inf = 1e18, mx = (int)1e9 + 1;
int find(int pos) {
    int it = lower_bound(vt.begin(), vt.end(), pos) - vt.begin() + 1;
    return it;
}
ll cost(int L, int R) {
    assert(L <= R);
    return ti - T.get(find(L));
}
ll get_val(qwq q, int x) {
    if(x < q.pos) return inf;
    return q.d + cost(q.pos, x) * 1ll * t[q.v];
}
ll gdp(int v, int pos) {
    while(!d[v].empty() && d[v][0].r < pos) {
        d[v].pop_front();
    }
    if(d[v].empty()) return inf;
    ll ret = min(inf, get_val(d[v][0], pos));
    return ret;
}

void add(int v, ll dd, int pos) {
    qwq nv;
    nv.pos = pos;nv.d = dd;nv.v = v;
    while(!d[v].empty() && get_val(d[v].back(), d[v].back().l) > get_val(nv, d[v].back().l)) {
        d[v].pop_back();
    }
    if(d[v].empty()) {
        d[v].push_back({pos, dd, pos, mx, v});
        return;
    }
    int l = d[v].back().l, r = mx + 1;
    while(r - l > 1) {
        int mid = (l + r) >> 1;
        if(get_val(d[v].back(), mid) <= get_val(nv, mid)) {
            l = mid;
        } else {
            r = mid;
        }
    }
    d[v].back().r = r - 1;
    if(r <= mx) {
        nv.l = r;
        nv.r = mx;
        d[v].push_back(nv);
    } 
}
ll get() {
    vector<int> e, ej;
    for(int i = 0; i < m; i++) {
        e.push_back(i);
        ej.push_back(i);
    }
    sort(e.begin(), e.end(), [&](int x, int y){
        return a[x] < a[y];
    });
    sort(ej.begin(), ej.end(), [&](int x, int y){
        return b[x] < b[y];
    });
    add(0, 0, 0);
    for(int i:e) {
        while(it < m && b[ej[it]] <= a[i]) {
            int j = ej[it];
            add(y[j], dp[j], b[j]);
            it++;
        }
        while(ti < w && f[ti].second < a[i]) {
            col++;
            T.upd(find(f[ti].first), 1);
            ti++;
        }
        dp[i] = gdp(x[i], a[i]) + c[i];
    }
    if(dp[m - 1] >= inf) dp[m - 1] = -1;
    return dp[m - 1];
}


ll solve(int N, int M, int W, vector<int> _T, vector<int> X, vector<int> Y, vector<int> A, vector<int> B, vector<int> C, vector<int> L,vector<int> R) {
    n = N;m = M;w = W;
    t = _T;x = X;y = Y; a = A; b = B; c = C;
    m++;
    x.push_back(n - 1);
    y.push_back(n - 1);
    a.push_back(mx);
    b.push_back(mx + 1);
    c.push_back(0);
    for(int i = 0; i < w; i++) {
        vt.push_back(L[i]);
        vt.push_back(R[i]);
        f.emplace_back(L[i], R[i]);
    }
    for(int i = 0; i < m; i++) {
        vt.push_back(a[i]);
        vt.push_back(b[i]);
    }
    vt.push_back(0);
    sort(vt.begin(), vt.end());
    vt.resize(unique(vt.begin(), vt.end()) - vt.begin());
    T.init((int)vt.size());
    sort(f.begin(), f.end(), [&](pair<int, int> x, pair<int, int> y){
        return x.second < y.second;
    });
	return get();
}

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 0 / 30
• Subtask 4: 0 / 60