Submission #1103744

#TimeUsernameProblemLanguageResultExecution timeMemory
1103744Mike_VuIntergalactic ship (IZhO19_xorsum)C++14
0 / 100
469 ms14160 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef unsigned long long ull; typedef long double dou; #define pii pair<int, int> #define fi first #define se second #define pb push_back #define MASK(x) (1LL<<(x)) #define BITj(x, j) (((x)>>(j))&1) template<typename T> bool maximize(T &x, const T &y) { if (x < y) {x = y; return 1;} return 0; } template<typename T> bool minimize(T &x, const T &y) { if (x > y) {x = y; return 1;} return 0; } namespace modulofunc{ const int mod = 1e9+7; int add(int x, int y) { ll temp = x+y; if (temp >= mod) temp -= mod; return temp; } void ad(int &x, int y) { x = add(x, y); } int sub(int x, int y) { ll temp = x-y; if (temp < 0) temp += mod; return temp; } int mul(int x, int y) { return 1LL*x*y%mod; } int binpow(int x, int k) { int res = 1; while (k > 0) { if (k&1) res = mul(res, x); k >>= 1; x = mul(x, x); } return res; } } using namespace modulofunc; const int maxn = 1005, lg = 7, maxq = 1e5+5; int n, a[maxn], q; int pw2[maxq]; int d[maxn][lg]; vector<int> inc[maxn][lg][lg]; //case 1 int d1[maxn][lg][lg]; //-= int ans = 0; void prep() { //2^i pw2[0] = 1; for (int i = 1; i < maxq; i++) { pw2[i] = mul(pw2[i-1], 2); } } int sumcomb(int n, bool j){ if (n == 0) return (j == 0); return pw2[n-1]; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); // #define name "task" // if (fopen(name".inp", "r")) { // freopen(name".inp", "r", stdin); // freopen(name".out", "w", stdout); // } prep(); //input cin >> n; for (int i = 1; i <= n; i++) { cin >> a[i]; } //tach bit from updates -> inc memset(d, 0, sizeof(d)); cin >> q; for (int i = 1; i <= q; i++) { int l, r, x; cin >> l >> r >> x; for (int j = 0; j < lg; j++) { if (BITj(x, j)) { // cout << j << ' '; d[l][j]++; d[r+1][j]--; for (int j2 = 0; j2 < lg; j2++) { if (BITj(x, j2)) { inc[r][j][j2].pb(l); } } } } } // cout << "\n"; //precal d ->2, 3 //cnt updates -> i for (int i = 1; i <= n; i++) { for (int j = 0; j < lg; j++) { d[i][j] += d[i-1][j]; } } // for (int j = 0; j < lg; j++) { // for (int i = 1; i <= n; i++) { // cout << d[i][j] << ' '; // } // cout << "\n"; // } //i: n-> 1 memset(d1, 0, sizeof(d1)); int allsum[lg][lg], cursum[lg][lg]; memset(allsum, 0, sizeof(allsum)); memset(cursum, 0, sizeof(cursum)); for (int i = n; i; i--) { //cal i for (int x = 0; x < lg; x++) { int valbit = pw2[2*x]; int valq = mul(pw2[q-d[i][x]], sumcomb(d[i][x], BITj(a[i],x)^1)); int valseg = mul(i, n-i+1); ad(ans, mul(mul(valbit, valq), valseg)); // int temp = mul(mul(valbit, valq), valseg); // if (temp > 0) { // cout << "case i: " << i << ' ' << x << ' ' << temp << "\n"; // } //allsumi for (int y = 0; y < lg; y++) { for (int id : inc[i][x][y]) { ++allsum[x][y]; d1[id][x][y]++; } cursum[x][y] = allsum[x][y]; } } //moi cap i, j: i -> 1 for (int j = i; j; j--) { //cnt updates i and j //every bit x y for (int x = 0; x < lg; x++) { for (int y = 0; y < lg; y++) { if (i == j && x <= y) continue; int valbit, valq, valseg; int case1 = cursum[x][y]; int case2 = d[j][y]-case1; int case3 = d[i][x]-case1; valbit = pw2[x+y+1]; bool biti = BITj(a[i], x), bitj = BITj(a[j], y); valq = mul(mul(sumcomb(case3, biti^1), sumcomb(case2, bitj^1)), sumcomb(case1, 0)); //1 - 1 ad(valq, mul(mul(sumcomb(case3, biti), sumcomb(case2, bitj)), sumcomb(case1, 1))); //0 - 0 valq = mul(valq, pw2[q-case1-case2-case3]); //case4 valseg = mul(j, n-i+1); ad(ans, mul(mul(valbit, valq), valseg)); // int temp = mul(mul(valbit, valq), valseg); // if (temp > 0) { // cout << "case bit: " << j << ' ' << i << ' ' << y << ' ' << x << "\n"; // cout << case1 << ' ' << case2 << ' ' << case3 << ' ' << valbit << ' ' << valq << ' ' << valseg << ' ' << temp << "\n"; // cout << bitj << ' ' << biti << ' '; // cout << mul(mul(sumcomb(case3, biti^1), sumcomb(case2, bitj^1)), sumcomb(case1, 0)) << ' '; // cout << mul(mul(sumcomb(case3, biti), sumcomb(case2, bitj)), sumcomb(case1, 1)) << ' '; // cout << pw2[q-case1-case2-case3] << "\n"; // } //reset cursum[x][y] -= d1[j][x][y]; } } //contribute to the sum } } cout << ans; } /* 2 1 3 1 1 2 2 */
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