Submission #1100084

#	Time	Username	Problem	Language	Result	Execution time	Memory
1100084		ShaShi	Crossing (JOI21_crossing)	C++17	26 / 100	7078 ms	18980 KiB

Main

#include <bits/stdc++.h>
 
#define int long long 
 
// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")
 
#define F first 
#define S second
#define mp make_pair
#define pb push_back
#define all(x) x.begin(), x.end()
#define kill(x) cout << x << "\n", exit(0);
#define pii pair<int, int>
#define pll pair<long long, long long>
#define endl "\n"
 
 
 
using namespace std;
typedef long long ll;
// typedef __int128_t lll;
typedef long double ld;
 
 
const int MAXN = (int)1e6 + 7;
const int MOD[] = {(int)1e9 + 11, 998244853};
const int B[] = {34, 9};
const ll INF = (ll)1e9 + 7;


 
int n, m, k, tmp, t, tmp2, tmp3, tmp4, u, v, w, flag, q, ans, N, X, Y, inv2;
int arr[MAXN], p[2][MAXN];
string Ss[3], T; char ch;
set<pii> st;


inline void check(pii x) { 
    if (st.find(x) == st.end()) cout << "No\n";
    else cout << "Yes\n"; 
}


inline string cross(string u, string v) {
    string res = "";

    for (int i=0; i<n; i++) {
        if (u[i] == v[i]) res.pb(u[i]);
        else if (u[i] != 'I' && v[i] != 'I') res.pb('I');
        else if (u[i] != 'O' && v[i] != 'O') res.pb('O');
        else res.pb('J');
    }

    return res;
}


inline int _get_hash(string s, int ind) {
    int res = 0;

    for (int i=0; i<n; i++) {
        if (s[i] == 'J') res = (res*B[ind] + 0)%MOD[ind];
        else if (s[i] == 'O') res = (res*B[ind] + 1)%MOD[ind];
        else res = (res*B[ind] + 2)%MOD[ind];
    }

    return res;
}

inline pii get_hash(string s) { return {_get_hash(s, 0), _get_hash(s, 1)}; }



int32_t main() {
    #ifdef LOCAL
    freopen("inp.in", "r", stdin);
    freopen("res.out", "w", stdout);
    #else
    ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    #endif

    cin >> n;

    cin >> Ss[0] >> Ss[1] >> Ss[2];

    for (int j=0; j<2; j++) {
        p[j][0] = 1;
        for (int i=1; i<MAXN; i++) p[j][i] = p[j][i-1]*B[j]%MOD[j];
    }

    for (int i=0; i<3; i++) {
        st.insert(get_hash(Ss[i]));
       
        for (int j=0; j<3; j++) st.insert(get_hash(cross(Ss[i], Ss[j])));
        for (int j=0; j<3; j++) for (int k=0; k<3; k++) st.insert(get_hash(cross(cross(Ss[i], Ss[j]), Ss[k])));
    }

    cin >> q >> T; check(get_hash(T));

    while (q--) {
        cin >> u >> v >> ch;

        for (int i=u-1; i<v; i++) T[i] = ch;

        check(get_hash(T));
    }


    return 0;
}

• Subtask 1: 3 / 3
• Subtask 2: 0 / 23
• Subtask 3: 23 / 23
• Subtask 4: 0 / 51