Submission #1099868

#TimeUsernameProblemLanguageResultExecution timeMemory
1099868model_codeHieroglyphs (IOI24_hieroglyphs)C++17
0 / 100
806 ms2097152 KiB
// failed/author-quadratic.cpp #include<bits/stdc++.h> #include "hieroglyphs.h" using namespace std; using vi = vector<int>; using vvi = vector<vi>; vi lcs(const vi& a, const vi& b) { int n = a.size(); int m = b.size(); vvi dp(n+1, vi(m+1)); for (int i=1; i <= n; ++i) { for (int j=1; j <= m; ++j) { dp[i][j] = max(dp[i-1][j], dp[i][j-1]); if (a[i-1] == b[j-1]) dp[i][j] = max(dp[i][j], dp[i-1][j-1]+1); } } vi c; int ci = n; int cj = m; while (ci > 0 && cj > 0) { if (a[ci-1] == b[cj-1] && dp[ci][cj] == dp[ci-1][cj-1]+1) { c.push_back(a[ci-1]); ci--; cj--; } else { if (dp[ci][cj] == dp[ci-1][cj]) { ci--; } else { cj--; } } } reverse(c.begin(), c.end()); return c; } vector<int> ucs(vi a, vi b) { vi c = lcs(a, b); int n = a.size(); int m = b.size(); int l = c.size(); vvi nxt(max(n, m)+1, vi(l+2, l)); //nxt[x][i] = first k such that c[k] = x and k >= i, l if such k does not exist for (int i=0; i < l; ++i) { for (int j=0; j <= i; ++j) { nxt[c[i]][j] = min(nxt[c[i]][j], i); } } vvi dp(n+1, vi(m+1, -1)); //dp[i][j] = maximum k so that there is a common subseq of a[0..i), b[0..j) which is not a subseq of c[0..k), -1 if no subseq for (int i=1; i <= n; ++i) { for (int j=1; j <= m; ++j) { if (a[i-1] == b[j-1]) { dp[i][j] = nxt[a[i-1]][dp[i-1][j-1]+1]; } dp[i][j] = max(dp[i][j], max(dp[i-1][j], dp[i][j-1])); } } if(dp[n][m] == l) return vector<int>({-1}); return c; }
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