Submission #1097849

#	Time	Username	Problem	Language	Result	Execution time	Memory
1097849		jerzyk	Game (APIO22_game)	C++17	0 / 100	12 ms	48472 KiB

game

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
using namespace __gnu_pbds;
using namespace std;
#define pb push_back
#define st first
#define nd second
typedef long long ll;
typedef long double ld;
const ll I = 1000LL * 1000LL * 1000LL * 1000LL * 1000LL * 1000LL;
const int II = 2 * 1000 * 1000 * 1000;
const ll M = 1000LL * 1000LL * 1000LL + 7LL;
const int N = 1000 * 1000 + 7;
int n, q;
vector<int> ed[N], red[N];
int p[N], k[N], cnt[N];
bool answer;

bool Chk(int a, int b, int r)
{
    if(r == 0) return false;
    return !(((1<<r) & a) ^ ((1<<r) & b));
}

void Upd(int v)
{
    if(p[v] > k[v] || (v >= q && p[v] >= k[v])) answer = true;
    //cerr << "U: " << v << " " << p[v] << " " << k[v] << " " << answer << "\n";
    if(answer) return;

    if(!Chk(p[v], k[v], cnt[v])) return;
    while(Chk(p[v], k[v], cnt[v])) --cnt[v];
    for(int i = 0; i < (int)ed[v].size(); ++i)
        if(p[ed[v][i]] < p[v])
        {
            p[ed[v][i]] = p[v];
            Upd(ed[v][i]);
        }
    for(int i = 0; i < (int)red[v].size(); ++i)
        if(k[red[v][i]] > k[v])
        {
            k[red[v][i]] = k[v];
            Upd(red[v][i]);
        }
}

void init(int _n, int _k)
{
    n = _n; q = _k;
    for(int i = 0; i < q; ++i)
    {
        p[i] = i + 1; k[i] = i + 1;
    }
    for(int i = q; i < n; ++i)
    {
        p[i] = 0;
        k[i] = q + 1;
        cnt[i] = 20;
    }
    for(int i = 0; i < n; ++i)
        while(Chk(p[i], k[i], cnt[i]))
            --cnt[i];
}

int add_teleporter(int u, int v)
{
    //cerr << "EDGE: " << u << " " << v << "\n";
    ed[u].pb(v); red[v].pb(u);
    if(p[v] < p[u])
    {
        p[v] = p[u];
        Upd(v);
    }
    if(k[u] > k[v])
    {
        k[u] = k[v];
        Upd(u);
    }
    if(answer)
        return 1;
    return 0;    
}

• Subtask 1: 0 / 2
• Subtask 2: 0 / 10
• Subtask 3: 0 / 18
• Subtask 4: 0 / 30
• Subtask 5: 0 / 40