Submission #1097568

#TimeUsernameProblemLanguageResultExecution timeMemory
1097568vjudge1Museum (CEOI17_museum)C++17
80 / 100
534 ms1048576 KiB
#include <bits/stdc++.h> #define ll long long #define ull unsigned ll #define pb push_back #define pa pair<int, int> #define pall pair<ll, int> #define fi first #define se second #define TASK "test" #define Size(x) (int) x.size() #define all(x) x.begin(), x.end() using namespace std; template<typename T1, typename T2> bool mini (T1 &a, T2 b) {if(a > b) a = b; else return 0; return 1;} template<typename T1, typename T2> bool maxi (T1 &a, T2 b) {if(a < b) a = b; else return 0; return 1;} const int MOD = 1e9 + 7; const int LOG = 20; const int maxn = 1e4 + 7; const ll oo = (ll) 1e9 + 69; int n, k, x, u, v, w, sz[maxn], dp[maxn][maxn][2], f[maxn][maxn][2]; vector<pa> g[maxn]; void dfs(int u, int par) { for(auto e:g[u]) { int v = e.fi; if(v == par) continue; dfs(v, u); } for(int i = 0; i <= Size(g[u]); i++) { for(int j = 0; j <= k; j++) { for(int t = 0; t < 2; t++) { f[i][j][t] = oo; } } } f[0][1][1] = 0; f[0][1][0] = 0; // f[0][0][0] = 0; // f[0][0][1] = 0; sz[u] = 1; for(int i = 1; i <= Size(g[u]); i++) { int v = g[u][i - 1].fi; int w = g[u][i - 1].se; if(v == par) { for(int j = 0; j <= sz[u]; j++) { for(int t = 0; t < 2; t++) { f[i][j][t] = f[i - 1][j][t]; } } continue; } for(int j = 0; j <= sz[u]; j++) { for(int pre = 0; pre <= sz[v]; pre++) { int cost = w * (pre > 0); mini(f[i][j + pre][0], f[i - 1][j][0] + dp[v][pre][1] + 2 * cost); mini(f[i][j + pre][0], f[i - 1][j][1] + dp[v][pre][0] + cost); mini(f[i][j + pre][1], f[i - 1][j][1] + dp[v][pre][1] + 2 * cost); } } sz[u] += sz[v]; } for(int i = 0; i <= k; i++) { for(int t = 0; t < 2; t++) { dp[u][i][t] = f[Size(g[u])][i][t]; } } dp[u][0][0] = dp[u][0][1] = 0; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); //freopen(TASK".inp", "r", stdin); //freopen(TASK".out", "w", stdout); cin>>n>>k>>x; for(int i = 1; i < n; i++) { cin>>u>>v>>w; g[u].pb({v, w}); g[v].pb({u, w}); } dfs(x, 0); cout<<min(dp[x][k][0], dp[x][k][1]); return 0; }
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