Submission #1096579

#	Time	Username	Problem	Language	Result	Execution time	Memory
1096579		dosts	Knapsack (NOI18_knapsack)	C++17	73 / 100	1095 ms	2828 KiB

knapsack

//SİGUSMUS SEFEROĞLU
#include <bits/stdc++.h>
#pragma GCC target("avx2,bmi,bmi2,popcnt,lzcnt")
using namespace std;
#define int int64_t
#define pii pair<int,int>
#define ff first
#define ss second
#define sp << " " <<    
#define all(cont) cont.begin(),cont.end()
#define vi vector<int>
const int MOD = 1e9+7,inf = 2e18;
const int N = 2e5+50,Q = 2e5+50;

int alloc[3000];

struct MagicianArray {
    int ptr = 0;
    int sz = 0;

    inline int front() {
        return alloc[ptr];
    }
    inline int back() {
        return alloc[ptr+sz-1];
    }
    inline void push_back(int x) {
        alloc[ptr+sz] = x;
        sz++;
    }
    inline void pop_back() {
        sz--;
    }
    inline void pop_front() {
        ptr++;
        sz--;
    }
};
void solve() { 
    int n,w;
    cin >> w >> n;
    vi v(n+1),c(n+1),k(n+1);
    for (int i=1;i<=n;i++) cin >> v[i] >> c[i] >> k[i];
    int*sack=new int[w+1],*sack2=new int[w+1];
    for (int i=0;i<=w+1;i++) sack2[i] = -inf;
    sack2[0] = 0;
    MagicianArray dq;
    for (int i=1;i<=n;i++) {
        for (int jj = 0;jj<c[i];jj++) {
            dq.sz = dq.ptr = 0;
            for (int j = jj;j<=w;j+=c[i]) {
                while (dq.sz && k[i] < (j-dq.front())/c[i]) {
                    dq.pop_front();
                }
                while (dq.sz && (j-dq.back())/c[i]*v[i]+sack2[dq.back()] <= sack2[j]) {
                    dq.pop_back();
                }
                dq.push_back(j);
                sack[j] = (j-dq.front())/c[i]*v[i]+sack2[dq.front()];
            }
        }
        swap(sack,sack2);
    }
    cout << *max_element(sack2,sack2+w+1) << endl;

}                       
                             
signed main() { 
    ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    #ifdef Dodi
        freopen("in.txt","r",stdin);
        freopen("out.txt","w",stdout);
    #endif
    int t = 1;
    //cin >> t; 
    while (t --> 0) solve();
}

• Subtask 1: 12 / 12
• Subtask 2: 17 / 17
• Subtask 3: 20 / 20
• Subtask 4: 24 / 24
• Subtask 5: 0 / 27