Submission #1094901

#	Time	Username	Problem	Language	Result	Execution time	Memory
1094901		raphaelp	Bouquet (EGOI24_bouquet)	C++14	0 / 100	37 ms	3524 KiB

Main

#include <bits/stdc++.h>
using namespace std;
class SegTree
{
private:
    vector<int> st;
    int N;
    int l(int x) { return (x << 1); }
    int r(int x) { return (x << 1) + 1; }
    void update(int L, int R, int a, int val, int x)
    {
        if (L > a || R < a)
            return;
        if (L == a && R == a)
        {
            st[x] = val;
        }
        else
        {
            int m = (L + R) / 2;
            update(L, m, a, val, l(x));
            update(m + 1, R, a, val, r(x));
            st[x] = max(st[l(x)], st[r(x)]);
        }
    }
    int RMQ(int L, int R, int a, int b, int x)
    {
        if (L > b || R < a)
            return 0;
        if (L >= a && R <= b)
            return st[x];
        int m = (L + R) / 2;
        return max(RMQ(L, m, a, b, l(x)), RMQ(m + 1, R, a, b, r(x)));
    }

public:
    SegTree(int x)
    {
        N = pow(2, ceil(log2(N)));
        st.assign(2 * N, 0);
    }
    void update(int x, int val) { update(0, N - 1, x, val, 1); }
    int RMQ(int a, int b)
    {
        if (a > b)
            return 0;
        else
            return RMQ(0, N - 1, a, b, 1);
    }
};
int main()
{
    int N;
    cin >> N;
    vector<int> lef(N), rig(N);
    for (int i = 0; i < N; i++)
    {
        cin >> lef[i] >> rig[i];
    }
    SegTree ST(N);
    vector<int> dp(N);
    priority_queue<pair<int, int>> PQ;
    int ans = 0;
    for (int i = 0; i < N; i++)
    {
        while (!PQ.empty() && -PQ.top().first < i)
        {
            ST.update(PQ.top().second, dp[PQ.top().second]);
            PQ.pop();
        }
        dp[i] = ST.RMQ(0, i - lef[i] - 1);
        dp[i]++;
        PQ.push({-(i + rig[i]), i});
        ans = max(ans, dp[i]);
    }
    cout << ans;
}

Compilation message (stderr)

Main.cpp: In function 'int main()':
Main.cpp:39:16: warning: 'ST.SegTree::N' may be used uninitialized in this function [-Wmaybe-uninitialized]
   39 |         N = pow(2, ceil(log2(N)));
      |             ~~~^~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 8
• Subtask 2: 0 / 16
• Subtask 3: 0 / 28
• Subtask 4: 0 / 18
• Subtask 5: 0 / 30