Submission #1094433

#TimeUsernameProblemLanguageResultExecution timeMemory
1094433stefanopulosIntercastellar (JOI22_ho_t1)C++17
100 / 100
49 ms9296 KiB
#include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <bits/stdc++.h> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ldb; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef pair<ldb,ldb> pdd; #define ff(i,a,b) for(int i = a; i <= b; i++) #define fb(i,b,a) for(int i = b; i >= a; i--) #define trav(a,x) for(auto& a : x) #define sz(a) (int)(a).size() #define fi first #define se second #define pb push_back #define lb lower_bound #define ub upper_bound #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; // os.order_of_key(k) the number of elements in the os less than k // *os.find_by_order(k) print the k-th smallest number in os(0-based) const int mod = 1000000007; const int inf = 1e9 + 5; const int mxN = 200005; int n, q; int niz[mxN]; int A[mxN]; ll pref[mxN]; int main(){ cin.tie(0)->sync_with_stdio(0); cin >> n; ff(i,1,n)cin >> niz[i]; ff(i,1,n){ int X = niz[i]; while(X % 2 == 0)X /= 2; pref[i] = pref[i - 1] + niz[i] / X; A[i] = X; } cin >> q; int j = 1; while(q--){ ll k; cin >> k; while(j + 1 <= n && k > pref[j])j += 1; cout << A[j] << '\n'; } return 0; } /* // probati bojenje sahovski */
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