Submission #1094368

#	Time	Username	Problem	Language	Result	Execution time	Memory
1094368		Rafat	Tracks in the Snow (BOI13_tracks)	C++14	100 / 100	743 ms	135592 KiB

tracks

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
#include <time.h>
#include <cstdlib>
#include <ctime>
#include <cstdio>
#include <cstring>

using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <iostream>

using namespace __gnu_pbds;
using namespace std;
template <class T>
using Tree =
    tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// to erase in multiset-> less_equal<T> and 
// s.erase(s.find_by_order(s.order_of_key(x)))
// lower_bound(x)=>(cannot use the stl lower_bound function)
// ll idx = s.order_of_key(x)
// if(idx == s.size()) -> no lower_bound
// else lb = *s.find_by_order(idx) // as 0-indexing
// idx-1 will give highest value which is strictly less than x
// for upper_bound->do the same with (x+1)

typedef long long ll;
typedef long double ld;
typedef pair<int,int> p32;
typedef pair<ll,ll> p64;
typedef tuple<ll, ll, ll> t64;
typedef vector<t64> vt64;
typedef vector<vt64> vvt64;
typedef pair<double,double> pdd;
typedef vector<ll> v64;
typedef vector<int> v32;
typedef vector<vector<int> > vv32;
typedef vector<vector<ll> > vv64;
typedef vector<vector<p64> > vvp64;
typedef vector<p64> vp64;
typedef vector<p32> vp32;
typedef vector<vector<p32> > vvp32;
typedef vector<bool> vb;
ll mod =  1e9+7, MOD = 998244353;
double eps = 1e-12;
// #define forn(i,e) for(ll i = 0; i < e; i++)
#define FOR(s, e, i) for(int i = s; i <= e; i++)
// #define rforn(i,s) for(ll i = s; i >= 0; i--)
#define ROF(s ,e, i) for(int i = s; i >= e; i--)
#define coutAll(A) for(auto asdafas : A) cout <<  asdafas << " "; cout << "\n";
#define foutAll(A) for(auto asdafas : A) fout <<  asdafas << " "; cout << "\n";
#define cinAll(A) for(auto &asdafas : A) cin >>  asdafas;
#define finAll(A) for(auto &asdafas : A) fin >>  asdafas;
#define minpq priority_queue<ll, v64, greater<ll>>
#define maxpq priority_queue<ll> 
#define ln "\n"
#define dbg(x) cout<<#x<<" = "<<x<<ln
#define mp make_pair
#define mt make_tuple
#define pb push_back
#define fi first
#define se second
ll inf = LLONG_MAX;
#define fast_cin() ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define sz(x) ((ll)(x).size())
#define yes cout<<"YES\n"
#define no cout<<"NO\n"
using namespace std;
typedef long long ll;
typedef vector<ll> vll;
typedef vector<vector<ll>> vvll;
typedef pair<ll, ll> pll;
typedef pair<ll, ll> pii;
//#define MAXN 1000000

void solve(int it)
{
    int h, w;
    cin>> h >> w;
    vector<string>A(h);
    cinAll(A);
    vv32 dist(h, v32(w,1e9));
    dist[0][0] = 1;
    deque<p32>q;
    q.push_front({0, 0});
    v32 dx = {1, -1, 0, 0};
    v32 dy = {0, 0, 1, -1};
    while(!q.empty()){
        auto u = q.front();
        // cout << u.fi << " " << u.se << "\n";
        q.pop_front();
        FOR(0, 3, i){
            int x = u.fi+dx[i];
            int y = u.se+dy[i];
            if(x < 0) continue;
            if(y < 0) continue;
            if(x >= h) continue;
            if(y >= w) continue;
            if(A[x][y] == '.') continue;
            if(A[x][y] == A[u.fi][u.se]){
                // same, 0-edge
                if(dist[x][y] > dist[u.fi][u.se]){
                    dist[x][y] = dist[u.fi][u.se];
                    q.push_front({x, y});
                }
            }
            else{
                // 1-edge;
                if(dist[x][y] > dist[u.fi][u.se]+1){
                    dist[x][y] = dist[u.fi][u.se]+1;
                    q.push_back({x, y});
                }
            }
        }
    }
    int ans = 1;
    FOR(0, h - 1, i){
        FOR(0, w - 1, j){
            if(A[i][j] == '.') continue;
            ans = max(ans, dist[i][j]);
        }
    }
    cout << ans;

}


int main()
{
    // fast_cin();    
    ll t = 1;
    // cin >> t;
    for(int it=1; it<=t; it++)
    {
        //cout << "Case " << it << ": ";
        solve(it);
    }
    return 0;
}

• Subtask 1: 30 / 30
• Subtask 2: 70 / 70