Submission #1094067

#	Time	Username	Problem	Language	Result	Execution time	Memory
1094067		stefanopulos	Advertisement 2 (JOI23_ho_t2)	C++17	100 / 100	488 ms	18448 KiB

Main

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ldb;
 
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ldb,ldb> pdd;

#define ff(i,a,b) for(int i = a; i <= b; i++)
#define fb(i,b,a) for(int i = b; i >= a; i--)
#define trav(a,x) for(auto& a : x)
 
#define sz(a) (int)(a).size()
#define fi first
#define se second
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k)  print the k-th smallest number in os(0-based)

const int mod = 1000000007;
const int inf = 2e9 + 5;
const int mxN = 500005; 

int n;
pii niz[mxN];

int id1[mxN];
bool cmp1(int i, int j){
    return niz[i].fi < niz[j].fi;
}

int id2[mxN];
bool cmp2(int i, int j){
    return niz[i].se > niz[j].se;
}

int pos[mxN];

struct SegTreeMX{
    int bor[4 * mxN];
    void build(int v, int tl, int tr){
        bor[v] = -inf;
        if(tl == tr)return;
        int mid = (tl + tr) / 2;
        build(v * 2, tl, mid); build(v * 2 + 1, mid + 1, tr);
    }
    void update(int v, int tl, int tr, int pos, int val){
        if(tl == tr){
            bor[v] = val;
            return;
        }
        int mid = (tl + tr) / 2;
        if(pos <= mid)update(v * 2, tl, mid, pos, val);
        else update(v * 2 + 1, mid + 1, tr, pos, val);
        bor[v] = max(bor[v * 2], bor[v * 2 + 1]);
    }
    int kveri(int v, int tl, int tr, int l, int r){
        if(tl > r || l > tr)return -inf;
        if(tl >= l && tr <= r)return bor[v];
        int mid = (tl + tr) / 2;
        return max(kveri(v * 2, tl, mid, l, r), kveri(v * 2 + 1, mid + 1, tr, l, r));
    }
}MX;

struct SegTreeMN{
    int bor[4 * mxN];
    void build(int v, int tl, int tr){
        bor[v] = inf;
        if(tl == tr)return;
        int mid = (tl + tr) / 2;
        build(v * 2, tl, mid); build(v * 2 + 1, mid + 1, tr);
    }
    void update(int v, int tl, int tr, int pos, int val){
        if(tl == tr){
            bor[v] = val;
            return;
        }
        int mid = (tl + tr) / 2;
        if(pos <= mid)update(v * 2, tl, mid, pos, val);
        else update(v * 2 + 1, mid + 1, tr, pos, val);
        bor[v] = min(bor[v * 2], bor[v * 2 + 1]);
    }
    int kveri(int v, int tl, int tr, int l, int r){
        if(tl > r || l > tr)return inf;
        if(tl >= l && tr <= r)return bor[v];
        int mid = (tl + tr) / 2;
        return min(kveri(v * 2, tl, mid, l, r), kveri(v * 2 + 1, mid + 1, tr, l, r));
    }
}MN;

int main(){
    cin.tie(0)->sync_with_stdio(0);

    cin >> n;
    ff(i,1,n)cin >> niz[i].fi >> niz[i].se;

    ff(i,1,n)id1[i] = id2[i] = i;
    sort(id1 + 1, id1 + n + 1, cmp1);
    sort(id2 + 1, id2 + n + 1, cmp2);

    ff(i,1,n)pos[id1[i]] = i;

    int br = 0; MX.build(1,1,n); MN.build(1,1,n);
    ff(i,1,n){
        int X = niz[id2[i]].fi;
        int E = niz[id2[i]].se;
        
        int L = MX.kveri(1,1,n,1,pos[id2[i]]);
        int R = MN.kveri(1,1,n,pos[id2[i]],n);
        if(X + E > L && R > X - E){
            br += 1;
        }

        MX.update(1,1,n,pos[id2[i]],X + E);
        MN.update(1,1,n,pos[id2[i]],X - E);

    }

    cout << br << '\n';

    return 0;
}
/*

4
4 2
2 3
3 4
6 5

// probati bojenje sahovski
*/
 
 
 
 
 

• Subtask 1: 10 / 10
• Subtask 2: 23 / 23
• Subtask 3: 36 / 36
• Subtask 4: 31 / 31