Submission #1091506

#	Time	Username	Problem	Language	Result	Execution time	Memory
1091506		thangdz2k7	Ski 2 (JOI24_ski2)	C++17	86 / 100	574 ms	877592 KiB

Main

// author : thembululquaUwU
// 3.9.2024

#include <bits/stdc++.h>
#define pb push_back
#define fi first
#define se second
#define endl '\n'

using namespace std;
using ll = long long;
using ii = pair <int, int>;
using vi = vector <int>;

const int MaxN = 2e5;
const int mod = 1e9 + 7;

void maxl(auto &a, auto b) {a = max(a, b);}
void minl(auto &a, auto b) {a = min(a, b);}

const ll inf = 1ll << 60;

template <int D, typename T>
struct Vec : public vector<Vec<D - 1, T>> {
    static_assert(D >= 1, "Dimension must be positive");
    template <typename... Args>
    Vec(int n = 0, Args... args) : vector<Vec<D - 1, T>>(n, Vec<D - 1, T>(args...)) {}
};

template <typename T>
struct Vec<1, T> : public vector<T> {
    Vec(int n = 0, T val = inf) : std::vector<T>(n, val) {}
};

#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define fd(sr, x) (lower_bound(sr.begin(), sr.end(), x) - sr.begin())
#define uq(sr) (sr).erase(unique(all((sr))), (sr).end())
#define szv(v) (int((v).size()))

int szhk(int n){
    return n * (n - 1) / 2;
}

void solve(){
    int n, k; cin >> n >> k;
    vector <int> sr(2 * n), h(n); vector <ll> c(n);
    for (int i = 0; i < n; ++ i) cin >> h[i] >> c[i], sr[i] = h[i], sr[i + n] = h[i] + 1;
    sort(all(sr)); uq(sr); int sz = szv(sr);
    vector <ll> cost(sz, inf); vi cnt(sz, 0);
    for (int i = 0; i < n; ++ i){
        int p = fd(sr, h[i]);
        minl(cost[p], c[i]); ++ cnt[p];
    }

    Vec <3, ll> dp(sz + 1, n + 1, n + 1);
    dp[0][1][0] = 0; ll ans = inf, mnc = inf;
    for (int i = 0; i < sz; ++ i){
        int w = n; if (i < sz - 1) w = sr[i + 1] - sr[i];
        for (int d = 1; d <= n; ++ d){
            for (int r = 0; r <= n; ++ r){
                ll now = dp[i][d][r];
                if (now == inf) continue;
                if (d < n) minl(dp[i][d + 1][r], now + mnc);
                int num = r + cnt[i]; ll co = 0, nr = 0;
                if (d * w < num) nr = num - d * w, co += 1ll * w * nr, num = d * w;
                int bl = num / d, re = num % d;
                co += 1ll * szhk(bl) * d + 1ll * re * bl; co *= k;
                minl(dp[i + 1][d][nr], now + co);
            }
        }
        minl(mnc, cost[i]);
    }
    for (int d = 1; d <= n; ++ d) minl(ans, dp[sz][d][0]);
    cout << ans;
}

int main(){
    if (fopen("pqh.inp", "r")){
        freopen("pqh.inp", "r", stdin);
        freopen("pqh.out", "w", stdout);
    }
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);

    int t = 1; // cin >> t;
    while (t --) solve();
    return 0;
}

Compilation message (stderr)

Main.cpp:18:11: warning: use of 'auto' in parameter declaration only available with '-fconcepts-ts'
   18 | void maxl(auto &a, auto b) {a = max(a, b);}
      |           ^~~~
Main.cpp:18:20: warning: use of 'auto' in parameter declaration only available with '-fconcepts-ts'
   18 | void maxl(auto &a, auto b) {a = max(a, b);}
      |                    ^~~~
Main.cpp:19:11: warning: use of 'auto' in parameter declaration only available with '-fconcepts-ts'
   19 | void minl(auto &a, auto b) {a = min(a, b);}
      |           ^~~~
Main.cpp:19:20: warning: use of 'auto' in parameter declaration only available with '-fconcepts-ts'
   19 | void minl(auto &a, auto b) {a = min(a, b);}
      |                    ^~~~
Main.cpp: In function 'int main()':
Main.cpp:80:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   80 |         freopen("pqh.inp", "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~
Main.cpp:81:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   81 |         freopen("pqh.out", "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 5 / 5
• Subtask 2: 12 / 12
• Subtask 3: 9 / 9
• Subtask 4: 33 / 33
• Subtask 5: 27 / 27
• Subtask 6: 0 / 14