# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
1089756 | rlx0090 | Split the sequence (APIO14_sequence) | C++14 | 1311 ms | 90444 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <cmath>
#include <limits>
#include <queue>
#include <string.h>
#include <stack>
#include <limits>
using namespace std;
int N, K;
int parent[205][100005];
long long p[100005], dp[2][100005];
long long inf = numeric_limits<long long>::max();
long long minf = numeric_limits<long long>::min();
struct line {
long long m, k;
double prev, next;
int l;
double cross(const line& o) {
return 1.0 * (o.k - k) / (m - o.m);
}
};
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin >> N >> K;
//N = 3;
//K = 2;
long long q;
for(int i = 1; i <= N; ++i) {
cin >> q;
//q = 1000;
p[i] = p[i - 1] + q;
}
int pv = 0;
int before = 0, cur = 0;
for(int k = 1; k <= K; ++k) {
before = k % 2; cur = (k + 1) % 2;
vector<line> lines;
for(int i = N - k - 1; i >= 0; --i) {
bool s = false;
line new_line = {p[i + 1], -p[i + 1] * p[i + 1] + p[N] * p[i + 1] + dp[before][i + 1], inf, minf, i + 1};
while(lines.size() > 0) {
if(new_line.m == lines.back().m) {
if(new_line.k > lines.back().k) {
lines.pop_back();
if(lines.size() > 0) new_line.prev = new_line.cross(lines.back());
} else s = true;
break;
}
if((new_line.prev = new_line.cross(lines.back())) >= lines.back().prev)
lines.pop_back();
else break;
}
if(!s && !lines.empty()) lines.back().next = lines.back().cross(new_line);
//cout << i << "th push back line : " << new_line. m << ", " << new_line.k << ", " << new_line.prev << ", " << new_line.next << endl;
//if(s) {cout << "before pv : " << pv << endl;}
if(!s) lines.push_back(new_line);
while(pv < lines.size() && lines[pv].next > p[i]) {
//cout << "pv next : " << lines[pv].next << " pi : " << p[i] << endl;
++pv;}
// if(s) {cout << "after pv : " << pv << endl;}
int z = lines.size() - 1;
pv = min(z, pv);
dp[cur][i] = p[i] * lines[pv].m + lines[pv].k - p[N] * p[i];
//cout << i << "th lines size : " << lines.size() << " pv : " << pv << " v : " << dp[cur][i] << endl;
//cout << "k : " << k << " i : " << i << " pv : " << pv << " c : " << dp[cur][i] << endl;
//cout << p[i] * lines[pv].m << ", " << lines[pv].k << ", " << - p[N] * p[i] << endl;
//cout << "p[n] : " << p[N] << " p[i] : " << p[i] << endl;
//cout << "line m : " << lines[pv].m << " line k : " << lines[pv].k << " p i : " << p[i] << endl;
parent[k][i] = lines[pv].l;
}
//cout << lines.size() << endl;
//cout <<"kth opt : " << dp[cur][0] << endl;
}
cout << dp[cur][0] << '\n';
int s = 0;
for(int k = K; k >= 1; --k) {
cout << parent[k][s] << ' ';
s = parent[k][s];
}
return 0;
}
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