Submission #1089248

#	Time	Username	Problem	Language	Result	Execution time	Memory
1089248		vjudge1	Kpart (eJOI21_kpart)	C++17	30 / 100	2081 ms	908 KiB

Main

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#define ll int
#define F first
#define S second
#define ull unsigned long long
#define db double
#define ldb long double
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define yes cout<<"YES\n"
#define no cout<<"NO\n"
#define ordered_set tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update>
#define all(x) x.begin(), x.end()

const int mod = 1e9 + 7;
const int N = 100001;

using namespace std;
using namespace __gnu_pbds;

ll n, m, k, p[N], f[N], a, b, dp[N], ans[N], cnt[N];
vector <ll> v, q;

signed main (){
	ios_base::sync_with_stdio(0);
	cin.tie(0); cout.tie(0);
	ll tt;
	cin >> tt;
	while (tt--){
		cin >> n;
		for (int i = 1; i <= n; i++){
			cin >> p[i];
			ans[i] = 1;
		}
		ans[1] = 0;
		for (int i = 1; i <= n; i++){
			dp[0] = 1;
			a = 0;
			cnt[0] = 1;
			cnt[p[i]] = 1;
			q.clear();
			q.pb(p[i]);
			q.pb(0);
			dp[p[i]] = 1;
			a += p[i];
			for (int y = i + 1; y <= n; y++){
				a += p[y];
				v.clear();
				for (int j = 0; j < q.size(); j++){
					if (cnt[q[j] + p[y]] == 0)v.pb (q[j] + p[y]), cnt[q[j] + p[y]] = 1;
					dp[q[j] + p[y]] = 1;
				}
				for (auto j: v){
					q.pb(j);
				}
				if (a % 2 == 1 || dp[a / 2] == 0){
					ans[y - i + 1] = 0;
				}
			}	
			for (auto y: q){
				dp[y] = 0;
				cnt[y] = 0;
			}
		}
		v.clear();
		for (int i = 1; i <= n; i++){
			if (ans[i]){
				v.pb (i);
			}
		}
		cout << v.size() << ' ';
		for (auto i: v){
			cout << i << ' ';
		}
		cout << '\n';
	}
}

Compilation message (stderr)

Main.cpp: In function 'int main()':
Main.cpp:54:23: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   54 |     for (int j = 0; j < q.size(); j++){
      |                     ~~^~~~~~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 0 / 70